在循环中创建列表

Question

我创建了一个“策划者”风格的游戏，用户可以在其中猜测计算机生成的确切数字序列。

我想添加一个存储先前猜测的功能，以便在进行下一次猜测之前可以将它们重播给用户

在我的脑海中和当前的程序布局中，我认为如果我可以创建一系列“pul”（以前的用户列表）会很好。

例如，当 while 循环运行并且“count”变量增加时，列表会被适当地命名。

cl, 电脑列表

ul，用户列表

ol，输出列表

pul，以前的用户列表

当 count = 0 时，用户输入创建 ul = [1, 3, 4, 8]

pul_0 = ul

'# 所以 pul_0 = [1, 3, 4, 8]

当 count = 1 时，用户为 ul = [2, 2, 9, 0] 创建新列表

pul_1 = ul

'# 所以 pul_1 = [2, 2, 9, 0]

'# 当然 pul_0 仍然 = [1, 3, 4, 8]

任何帮助表示赞赏，提前致谢。

如果需要，这里有一些代码可以提供更多细节，底部的完整程序可以提供更多上下文。

n = int(input("how many numbers to guess? (normally 4)"))

att = int(input("how many attempts? (normally 10)"))

count = 0
while count < att:

    ul = [int(input()) for i in range(n)]

    pul(count) = ul

    count = count + 1

我已经阅读了一些关于使用字典来解决这个问题的内容，但没有让它们为我工作， 在 python 的 for 循环中创建唯一名称列表

{'pul_{}'.format(count):[] for i in ul}

完整程序如下

n = int(input("how many numbers to guess? (normally 4)"))

att = int(input("how many attempts? (normally 10)"))

cl = [randint(0, 9) for i in range(n)]

wincount = 0
count = 0

while count < att:

    print(att-count, "attempts remaining. Please enter",n, "numbers, pressing enter between each")

    ul = [int(input()) for i in range(n)]



    wincount = 0
    nearcount = 0
    for i in range (n):

        if cl[i] == ul[i]:
            wincount = wincount + 1

        for j in range (n):
            if cl[i] == ul[j]:
                nearcount += 1

    nearcount = nearcount - wincount

    if wincount == n:
        print("winner")
        count = att + 1

    if wincount != n:
        print("you have", wincount,"correct numbers in the correct positions")
        print("you have a further", nearcount,"correct numbers, but they are in the wrong positions")
        count = count + 1




if count == att:

    print("no more attempts, game over")
    print("btw the correct answer was", cl)
elif count == att + 1:
    print("nice 1")


'''



I have read a small amount about using a dictionary to try and solve this issue, but i played around with it a little and didn't get very far.

Thanks in advance!

Answer 1

这是您修改的代码

n = int(input("how many numbers to guess? (normally 4)"))
att = int(input("how many attempts? (normally 10)"))
count = 0
pul = {}  # here're your previous lists, currently empty
while count < att:
    ul = [int(input()) for i in range(n)]
    pul[count] = ul  # you can use more flexible key value, as you mentioned
    count = count + 1
    # if you need to replay lists - you just use your "pul" dict
for i in range(count):
    print(f'your № {i} list was {pul.get(i)}')