[英]Powershell 2.0 extract certain files from zip (include subdirectories)
抱歉,这个问题分散在互联网上,但我还没有找到一个令人满意的答案,它只使用 Powershell 2.0(使用 .NET v3.5) -没有外部库或程序
我正在使用以下代码从ZipFile.zip
中提取log.txt
(无论log.txt
的位置)
$Destination = (new-object -com shell.application).NameSpace('C:\ZipExtractDir')
$ZipFile = (new-object -com shell.application).NameSpace('C:\ZipFile.zip')
$Destination.CopyHere(($Zipfile.Items() | where-object {$_.Name -like '*log.txt'}), 1044)
log.txt
在目录根\log.txt
中有效log.txt
位于子目录\Subfolder\log.txt
中,则失败{$_.Name -Like '*Subfolder\log.txt'}
则失败(双引号和单引号均失败)-eq
-like
-contains
''
""
$_.FullName
我很确定我过滤不正确 - 任何人都可以帮助处理这段代码,以便它也能解析子目录吗?
与您已经完成的类似,您可以像这样设置Shell.Application
命名空间。 然后您可以将提取的目录复制到目标路径。
$zipFilePath = "Zipfile.zip"
$destinationPath = "C:\Users\Public\Downloads"
$zipfile = (New-Object -Com Shell.Application).NameSpace($zipFilePath)
$destination = (New-Object -Com Shell.Application).NameSpace($destinationPath)
$destination.CopyHere($zipfile.Items())
然后列出log.txt
文件,我们可以使用Join-Path
构造完整的提取路径。 这基本上只是将System.IO.Path.GetFileNameWithoutExtension()
中的 zip 文件名附加到目标路径。 然后只需使用Get-ChildItem
使用-Recurse
和-Filter
开关以递归方式列出文件。
$extractedPath = Join-Path -Path $destinationPath -ChildPath ([System.IO.Path]::GetFileNameWithoutExtension($zipFilePath))
Get-ChildItem -Path $extractedPath -Filter log.txt -Recurse
为了测试PowerShell 2.0我们可以使用-version 2
和powershell.exe
:
powershell.exe -version 2 .\test.ps1
更新
如果要在提取之前检查文件,则需要自己递归目录。 下面是如何做到这一点的演示。
function New-ZipChildRootFolder
{
param
(
[string]$DestinationPath,
[string]$ZipFileName
)
$folderPath = Split-Path -Path $ZipFileName -Leaf
$destination = (New-Object -ComObject Shell.Application).NameSpace($DestinationPath)
$destination.NewFolder($folderPath)
}
function Get-ZipChildItems
{
param
(
[string]$ZipFilePath,
[string]$DestinationPath
)
$zipfile = (New-Object -ComObject Shell.Application).NameSpace($ZipFilePath)
$zipFileName = [System.IO.Path]::GetFileNameWithoutExtension($ZipFilePath)
Write-Output "Create root zip folder : $zipFileName"
New-ZipChildRootFolder -DestinationPath $DestinationPath -ZipFileName $zipFileName
foreach ($item in $zipFile.items())
{
Get-ZipChildItemsRecurse -Items $item -DestinationPath $DestinationPath -ZipFileName $zipFileName
}
}
function Get-ZipChildItemsRecurse
{
param
(
[object]$Items,
[string]$DestinationPath,
[string]$ZipFileName
)
foreach ($file in $Items.getFolder.Items())
{
if ($file.IsFolder -eq $true)
{
Write-Output "Creating folder : $($file.Path)"
New-ZipChildFolder -Folder $file -DestinationPath $DestinationPath -ZipFileName $ZipFileName
Get-ZipChildItemsRecurse -Items $file -DestinationPath $DestinationPath -ZipFileName $ZipFileName
}
else
{
$filename = Split-Path -Path $file.Path -Leaf
if ($filename -eq "log.txt")
{
Write-Output "Copying file : $($file.Path)"
New-ZipChildFile -File $file -DestinationPath $DestinationPath -ZipFileName $ZipFileName
}
}
}
}
function New-ZipChildFile
{
param
(
[object]$File,
[string]$DestinationPath,
[string]$ZipFileName
)
$destination = New-Object -ComObject Shell.Application
$items = $File.Path.Split("\")
$zipRootIndex = [array]::IndexOf($items, $ZipFileName)
$path = $items[$zipRootIndex..($items.Length - 2)] -join "\"
$fullPath = Join-path -Path $DestinationPath -ChildPath $path
$destination.NameSpace($fullPath).CopyHere($File)
}
function New-ZipChildFolder
{
param
(
[object]$Folder,
[string]$DestinationPath,
[string]$ZipFileName
)
$destination = New-Object -ComObject Shell.Application
$items = $Folder.Path.Split("\")
$zipRootIndex = [array]::IndexOf($items, $ZipFileName)
$folders = $items[$zipRootIndex..($items.Length - 1)]
$currentFolder = $DestinationPath
foreach ($folder in $folders)
{
$destination.NameSpace($currentFolder).NewFolder($folder)
$currentFolder = Join-Path -Path $currentFolder -ChildPath $folder
}
}
用法:
$zipFilePath = "C:\Zipfile.zip"
$destinationPath = "C:\Users\Public\Downloads"
Get-ZipChildItems -ZipFile $zipFilePath -DestinationPath $destinationPath
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