Python 为什么我的代码会导致无限循环？

Question

因此，我正在学习 Python 3。我尝试编写一个脚本，要求您猜测 1 到 20 之间的数字。现在我知道这不是最好的方法，但是当我运行代码时，它会进入无限环形。 是什么原因造成的？ 我做错了什么？ 我的问题的目的是了解我的错误以及导致错误的过程。 感谢你们。

# Defining the function inside which the verification happens
def guesst(secretNumber, inputNumber):
    numberOfGuesses = 0
    if inputNumber >= 1 and inputNumber <= 20:
        while inputNumber:
            if inputNumber > secretNumber:
                numberOfGuesses += 1
                print('Your guess is too high.')
            elif inputNumber < secretNumber:
                numberOfGuesses += 1
                print('Your guess is too low.')
            elif inputNumber == secretNumber:
                print('Your guess is correct, congratulations! You\'ve my number in ', numberOfGuesses, 'guesses.')
                break
    else:
        print('Please enter a number between 1 and 20')

# Defining the variables used by the function
secretNumber = 11
inputNumber = int(input('I\'m thinking of a number between 1 and 20, try to guess which one: '))

# Calling in the function
guesst(secretNumber, inputNumber)

# -------------------------------------------------------
# I just changed my code to this and it worked, thank you!
# -------------------------------------------------------

def guesstt(secretNumber):
    numberOfGuesses = 0
    while secretNumber:
        inputNumber = int(input('I\'m thinking of a number between 1 and 20, try to guess which one: '))
        if inputNumber >= 1 and inputNumber <= 20:
            if inputNumber > secretNumber:
                numberOfGuesses += 1
                print('Your guess is too high.')
            elif inputNumber < secretNumber:
                numberOfGuesses += 1
                print('Your guess is too low.')
            elif inputNumber == secretNumber:
                print('Your guess is correct, congratulations! You\'ve my number in ', numberOfGuesses, 'guesses.')
                break
        else:
            print('Please enter a number between 1 and 20')

secretNumber = 11
guesstt(secretNumber)

Answer 1

secretNumber 不变？ 在if和elif中使用 numberOfGuesses

Answer 2

阅读这两行：

 if inputNumber >= 1 and inputNumber <= 20: while inputNumber:

while循环体不会改变inputNumber 。 如果它在 1..10 或 12..20 范围内，则您的循环相当于while True:并且它将永远运行。 您可能希望在循环内部进行if测试，并且您肯定希望在您返回评估循环条件时更改该值，例如通过input一个新值。

Answer 3

变量 inputNumber 不会在 while 循环中更新。

尝试添加：

inputNumber = int(input("please try again"))

或者大意是允许用户在下一次迭代之前更新他们的猜测。

Answer 4

尝试这个

def guesst(secretNumber):

numberOfGuesses = 0

while True:
    inputNumber = int(input('I\'m thinking of a number between 1 and 20, try to guess which one: '))
    if inputNumber > secretNumber:
        numberOfGuesses += 1
        print('Your guess is too high.')
    elif inputNumber < secretNumber:
        numberOfGuesses += 1
        print('Your guess is too low.')
    elif inputNumber == secretNumber:
        print('Your guess is correct, congratulations! You\'ve my number in ', numberOfGuesses, 'guesses.')
        break
else:
    print('Please enter a number between 1 and 20')


# Defining the variables used by the function
snum = 11
guesst(snum)

当 while 循环重复时，您需要再次收集用户的输入，因此您的输入语句应该在 while 循环中，而不是在 function 之外。

您的 if 语句也应该在 while 循环内。