random.randint 似乎不起作用，我认为

Question

我正在猜数字“项目”，但我卡住了，当我运行它时，它要求我选择一个数字然后什么也没发生，这是代码：

import random

play_game = "y"

while (play_game == "y"):
    answer = random.randint(1, 100)
    try_number = input("Guess a number between 1 and 100: ")
    try_number = int(try_number)
    counter = 1

    while try_number != answer:
        if try_number > answer:
            print("Your number is too large")
        if try_number < answer:
            print("Your number is to small")
        try_number = int(input("Guess a number between 1 and 100: "))
        counter = counter + 1
    print("You got it! You tried " + str(counter) + "times")
    play_game = input("Continue? ")

感谢您的时间！

Answer 1

也许您在 Python 2 而不是 Python 3 上运行它？ 在 Python 2 上，您需要将“input”替换为“raw_input”，否则它会尝试对输入的内容进行eval() ，这不是您想要的。

Answer 2

因为您在标签中提到了 python 3，所以我假设这是 python 3（将raw_input用于 python 2）。 输入从 1 到 100 的数字后，您必须按回车键。当我尝试您的代码时，它没有问题。

import random

play_game = "y"

while (play_game == "y"):
    answer = random.randint(1, 100)
    try_number = input("Guess a number between 1 and 100: ")
    try_number = int(try_number)
    counter = 1

    while try_number != answer:
        if try_number > answer:
            print("Your number is too large")
        if try_number < answer:
            print("Your number is to small")
        try_number = int(input("Guess a number between 1 and 100: "))
        counter = counter + 1
    print("You got it! You tried " + str(counter) + "times")
    play_game = input("Continue? ")