random.randint 似乎不起作用，我認為

Question

我正在猜數字“項目”，但我卡住了，當我運行它時，它要求我選擇一個數字然后什么也沒發生，這是代碼：

import random

play_game = "y"

while (play_game == "y"):
    answer = random.randint(1, 100)
    try_number = input("Guess a number between 1 and 100: ")
    try_number = int(try_number)
    counter = 1

    while try_number != answer:
        if try_number > answer:
            print("Your number is too large")
        if try_number < answer:
            print("Your number is to small")
        try_number = int(input("Guess a number between 1 and 100: "))
        counter = counter + 1
    print("You got it! You tried " + str(counter) + "times")
    play_game = input("Continue? ")

感謝您的時間！

Answer 1

也許您在 Python 2 而不是 Python 3 上運行它？ 在 Python 2 上，您需要將“input”替換為“raw_input”，否則它會嘗試對輸入的內容進行eval() ，這不是您想要的。

Answer 2

因為您在標簽中提到了 python 3，所以我假設這是 python 3（將raw_input用於 python 2）。 輸入從 1 到 100 的數字后，您必須按回車鍵。當我嘗試您的代碼時，它沒有問題。

import random

play_game = "y"

while (play_game == "y"):
    answer = random.randint(1, 100)
    try_number = input("Guess a number between 1 and 100: ")
    try_number = int(try_number)
    counter = 1

    while try_number != answer:
        if try_number > answer:
            print("Your number is too large")
        if try_number < answer:
            print("Your number is to small")
        try_number = int(input("Guess a number between 1 and 100: "))
        counter = counter + 1
    print("You got it! You tried " + str(counter) + "times")
    play_game = input("Continue? ")