[英]I'm not receiving a message back on iOS while using Mqtt protocol with raspberry pi
我正在尝试将数据从 RPI 发送到 iOS 应用程序,该消息显示在 RPI 上,但不在 iOS 中
//this is the code on RPI
import paho.mqtt.client as MQTT
def connectionStatus(client, userdata, flag, rc):
print("Connecting...")
mqttClient.subscribe("rpi/hello")
def messageDecoder(client, userdata, msg):
message = msg.payload.decode(encoding='UTF-8')
if message == "this is iPhone":
print("Sending reply...")
mqttClient.publish("rpi/world", "this is 3b+")
clientName = "Pi"
serverAddress = "192.168.1.101"
mqttClient = MQTT.Client(clientName)
mqttClient.on_connect = connectionStatus
mqttClient.on_message = messageDecoder
mqttClient.connect(serverAddress)
mqttClient.loop_forever()
这里和 swift 上的代码我在这里尝试了很多方法,有人可以帮我解决这个问题!
import UIKit
import CocoaMQTT
protocol didReceiveMessageDelegate {
func setMessage(message: String)}
class ViewController: UIViewController {
let mqttClient = CocoaMQTT(clientID: "iOS Device", host: "192.168.1.101", port: 1883)
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view.
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
}
@IBAction func connect(_ sender: UIButton) {
mqttClient.connect()
}
@IBAction func disconnect(_ sender: UIButton) {
mqttClient.disconnect()
}
@IBOutlet weak var labelshow: UILabel!
@IBAction func send(_ sender: UIButton) {
mqttClient.publish("rpi/hello", withString: "this is iphone")
mqttClient.subscribe("rpi/world")
}
func mqtt(_ mqtt: CocoaMQTT, didReceiveMessage message: CocoaMQTTMessage, id: UInt16 ) {
let messageDecoded = String(bytes: message.payload, encoding: .utf8)
print("Did receive a message: \(messageDecoded!)")
}
func setMessage(message: String) {
labelshow.text = message}
}
您需要将视图 controller 设置为 MQTT 客户端的delegate
,否则不会调用didReceiveMessage
委托 function。
您需要 state 使您的 class 符合CocoaMQTTDelegate
然后分配委托
class ViewController: UIViewController, CocoaMQTTDelegate {
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view.
self.mqttClient.delegate = self
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.