如何使用 python 通过用户输入在范围内打印一定数量的结果？

Question

我试图创建一个骰子滚动程序，用户可以在其中输入他们想要滚动的一定数量的骰子。 但它不起作用。 我应该怎么办？

from random import branding
repeat = True
while repeat:
    amount = input('how many dice do you want to roll?')
    for i in range(0, amount):
       print("You rolled",randint(1,6))
    print("Do you want to roll again?")
    repeat = ("y" or "yes") in input().lower()

Answer 1

我是这门语言的新手，但我喜欢它，我打赌你也喜欢，因此我根据你的代码提出了一个想法，我当然希望这能回答你的问题。 继续编码兄弟，Python 很棒！

#First, you only need the random function to get the results you need :)
import  random
#Let us start by getting the response from the user to begin
repeat = input('Would you like to roll the dice [y/n]?\n')

#As long as the user keeps saying yes, we will keep the loop
while repeat != 'n':
# How many dices does the user wants to roll, 2 ,3 ,4 ,5  who knows. let's ask!
    amount = int(input('How many dices would you like to roll? \n'))
# Now let's roll each of those dices and get their results printed on the screen
    for i in range(0, amount):
       diceValue = random.randint(1, 6)
       print(f"Dice {i+1} got a [{diceValue}] on this turn.")
#Now, let's confirm if the user still wants to continue playing.       
    repeat = input('\nWould you like to roll the dice [y/n]?\n')

# Now that the user quit the game, let' say thank you for playing
print('Thank you for playing this game, come back soon!')
# Happy Python Coding, buddy! I hope this answers your question.

Answer 2

在第 4 行，您刚刚做了input() 。 但是，您需要在输入周围添加一个int() function。

这将是您的代码：

from random import *
repeat = True
while repeat:
    amount = int(input('how many dice do you want to roll?'))
    for i in range(0, amount):
       print("You rolled",randint(1,6))
    print("Do you want to roll again?")
    repeat = ("y" or "yes") in input().lower()

希望这可以帮助！

Answer 3

1. 您正在从random模块导入branding ，而不是randint 。

2. 调用input() function 时使用int() ，以使range() function 正常工作。

3. 在最后一行， repeat = ("y" or "yes") in input().lower() ， ("y" or "yes")将评估为 boolean，然后您的检查将变为True in input().lower()给出不正确和奇怪的结果。 repeat = input().lower() in ("y", "yes")东西。