将字典的键与参考列表匹配并获取值

Question

我正在处理字典的问题并且遇到了障碍，所以我有一个 3D 列表，其中包含用于参考的坐标和一个字典，其键与列表中的坐标匹配，我需要的是，如果键和然后，坐标匹配 append 另一个 3D 列表中的值。 我几乎知道该怎么做，但我没有得到我想要的，这就是我尝试过的：

reference = [[[2, 3], [2, 4], [3, 2], [4, 2]], 
             [[2, 3], [3, 2], [3, 4], [4, 3]], 
             [[2, 3], [3, 2], [3, 4], [4, 3]]]

mydict = {(2, 3): [5, 1], (2, 4): [14, 16], (3, 2): [19, 1], (3, 4): [14, 30], (4, 2): [16, 9], (4, 3): [6, 2]}

aux = [[tuple(j) for j in i] for i in reference] #This transform the 3D list to tuples to match the keys

print(aux)

aux = [[(2, 3), (2, 4), (3, 2), (4, 2)], [(2, 3), (3, 2), (3, 4), (4, 3)], [(2, 3), (3, 2), (3, 4), (4, 3)]]

aux_list = []
    for key, value in mydict.items():
        final_list =[]
        for i in aux:
            for j in i:                    #If the key matches the list of tuples then append the value
                if j == key:
                    aux_list.append(value)
        final_list.append(aux_list)

print(final_list)

final_list = [[[5, 1], [5, 1], [5, 1], [14, 16], [19, 1], [19, 1], [19, 1], [14, 30], [14, 30], [16, 9], [6, 2], [6, 2]]]

这给了我正确的值，但是它的顺序有点混乱，虽然它是 3D 列表，但它不像参考列表，这应该是我想要的 output：

final_list = [[[5, 1], [14, 16], [19,  1], [16, 9]],
              [[5, 1], [19,  1], [14, 30], [6,  2]],
              [[5, 1], [19,  1], [14, 30], [6,  2]]]

这只是一个例子，我相信绝对应该有一个简单的方法来做到这一点，但我有点新手，所以我不确定问题到底是什么，所以任何帮助或参考将不胜感激，非常感谢！

Answer 1

reference = [[[2, 3], [2, 4], [3, 2], [4, 2]],
             [[2, 3], [3, 2], [3, 4], [4, 3]],
             [[2, 3], [3, 2], [3, 4], [4, 3]]]

mydict = {(2, 3): [5, 1], (2, 4): [14, 16], (3, 2): [19, 1], (3, 4): [14, 30], (4, 2): [16, 9], (4, 3): [6, 2]}


out = [[mydict.get(tuple(v), v) for v in row] for row in reference]

from pprint import pprint
pprint(out)

印刷：

[[[5, 1], [14, 16], [19, 1], [16, 9]],
 [[5, 1], [19, 1], [14, 30], [6, 2]],
 [[5, 1], [19, 1], [14, 30], [6, 2]]]