[英]Find the most frequent words that appear in the dataset
我写了一个 function 作为输入列表并返回列表中最常见的项目。
##Write the function
def most_frequent(List):
dict = {}
count, itm = 0, ''
for item in reversed(List):
dict[item] = dict.get(item, 0) + 1
if dict[item] >= count :
count, itm = dict[item], item
return(item)
return num
# verfiy the code
list = [5,42,34,6,7,4,2,5]
print(most_frequent(list))
然后下载两个文本文件以获取最常用的单词。
# Download the files restaurants.txt and restaurant-names.txt from Github
!curl https://raw.githubusercontent.com/ipeirotis/introduction-to-python/master/data/restaurant-names.txt -o restaurant-names.txt
!curl https://raw.githubusercontent.com/ipeirotis/introduction-to-python/master/data/restaurants.txt -o restaurants.txt
# create the list from the restaurants.txt
List = open("restaurants.txt").readlines()
# get the most most frequent restaurant names
print("The most frequent restaurant names is ",most_frequent(List))
print(most_common(List))
但是当我试图找到出现在餐厅名称中最常见的词时。 我得到了同样的结果。 你能帮忙检查一下这是否正确吗? 谢谢
# create the list from the restaurants.txt
List = open("restaurants.txt").readlines()
# get the most most frequent restaurant names
print("The most frequent restaurant names is ",most_frequent(List))
它是return itm
(最常见的项目)而不是return item
(你的反向列表的最后一部分)
似乎您可能为餐厅名称文件使用了错误的文件名。 从您的 curl 命令来看:
:curl https.//raw.githubusercontent.com/ipeirotis/introduction-to-python/master/data/restaurant-names.txt -o restaurant-names.txt
你应该使用的文件名是restaurant-names.txt
所以你的代码应该是:
# create the list from the restaurants.txt
List = open("restaurants-names.txt").readlines()
# get the most most frequent restaurant names
print("The most frequent restaurant names is ",most_frequent(List))
可能是 function 出错了,如果您尝试相同的测试数据但顺序不同,例如: list = [42,5,34,6,5,7,4,2]
而不是list = [5,42,34,6,7,4,2,5]
,output还是5吗?
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