重新排列 seaborn countplot x 轴

Question

我在 pandas 数据系列上使用 seaborn 计数图。 该系列看起来像这样：

df['col'] = 

['Week 4',
 'Week 4',
 'Week 3',
 'Week 1',
 'Week 5',
 'Week 3',
 'Week 3',
 'Week 2',
 'Week 4',
 'Week 5',
 'Week 5',
 'Week 4',
 'Week 5',
 'Week 2',
 'Week 5',
 'Week 1',
 ..
 ..
 ..
 ..
]

我想重新排列 x 轴，从第 1 周、第 2 周、第 3 周开始……等等。

sns.countplot(LeaseComp['Weeks on market'])

Answer 1

您可以对值进行排序，例如：

L = ['Week 4',
 'Week 4',
 'Week 3',
 'Week 1',
 'Week 5',
 'Week 3',
 'Week 3',
 'Week 2',
 'Week 4',
 'Week 5',
 'Week 5',
 'Week 4',
 'Week 5',
 'Week 2',
 'Week 5',
 'Week 1',

]
LeaseComp = pd.DataFrame(L, columns=['Weeks on market'])

sns.countplot(LeaseComp['Weeks on market'].sort_values())

Answer 2

对于 seaborn：

sns.countplot( x = 'Weeks on market', data = LeaseComp, 
              order = sorted(LeaseComp['Weeks on market'].unique()))

BEATHUB 发布的内容可以实现相同的 plot，但它可能会产生一些警告。

Answer 3

你可以试试，

sns.countplot(x= LeaseComp['Weeks on market'].sort_values())