[英]Finding the latitude and longitude values for the device's current location in Android with Google Maps API
因此,基于此提出了许多类似的问题,我也得到了一个可行的解决方案。 但是,这似乎只适用于我的物理 Android 设备。 如果我将它与模拟器一起使用,该方法会返回 null 值,我不知道为什么。 许多消息来源提到我目前使用的代码有更好的替代方案,但他们没有提到具体是什么/如何。 这是我用来获取设备当前位置的代码:
@SuppressWarnings("MissingPermission")
private LatLng getCurrentLocation() {
LocationManager locationManager = (LocationManager) this.getSystemService(Context.LOCATION_SERVICE);
String locationProvider = LocationManager.NETWORK_PROVIDER;
assert locationManager != null;
android.location.Location lastKnownLocation = locationManager.getLastKnownLocation(locationProvider);
return new LatLng(lastKnownLocation.getLatitude(), lastKnownLocation.getLongitude());
}
我也不喜欢我必须压制警告的事实。 我看过的资料包括:
https://developer.android.com/training/location/retrieve-current.html#java
在 Android 上获取用户当前位置的最简单、最可靠的方法是什么?
第一个不起作用,我得到一个 null 值。 对于我正在寻求的简单结果,第二个看起来过于复杂。
这段代码在我的一个项目中运行良好:
public class LocationManager {
private static LocationManager requestManager;
private FusedLocationProviderClient mLocationProviderClient;
private Location mLocation;
private Location mMyCurrentLocation;
private locationSuccessListener mListener;
public Location getLocation() {
return mLocation;
}
public void setLocation(Location location) {
mLocation = location;
}
private LocationManager(FusedLocationProviderClient fusedLocationProviderClient) {
this.mLocationProviderClient = fusedLocationProviderClient;
}
public static LocationManager createInstance(FusedLocationProviderClient fusedLocationProviderClient) {
if (requestManager != null) {
return requestManager;
} else {
return requestManager = new LocationManager(fusedLocationProviderClient);
}
}
public static LocationManager getInstance() {
return requestManager;
}
public void setLocation(Activity activity) {
mListener = (locationSuccessListener) activity;
LocationCallback callback = new LocationCallback();
LocationRequest locationRequest = new LocationRequest();
Task<Void> r = mLocationProviderClient.requestLocationUpdates(locationRequest, callback, Looper.getMainLooper());
r.addOnSuccessListener(new OnSuccessListener<Void>() {
@Override
public void onSuccess(Void aVoid) {
mLocationProviderClient.getLastLocation().addOnSuccessListener(activity, new OnSuccessListener<Location>() {
@Override
public void onSuccess(Location location) {
mMyCurrentLocation = location;
mLocation = location;
if (location != null) {
mListener.onLocationReceived();
mLocationProviderClient.removeLocationUpdates(callback);
}
}
});
}
});
}
public Location getMyCurrentLocation() {
return mMyCurrentLocation;
}
public interface locationSuccessListener {
void onLocationReceived();
}
你需要做这样的事情:
public class PlacesActivity extends SingleFragmentActivity implements NavigationView.OnNavigationItemSelectedListener, LocationManager.locationSuccessListener
然后在你的活动中你会得到这个:
@Override
public void onLocationReceived() {
Location l = LocationManager.getInstance().getMyCurrentLocation();
if (l==null){
Toast.makeText(this, "unable to get location", Toast.LENGTH_SHORT).show();
}
}
要获得许可,您应该执行以下操作:
if (ContextCompat.checkSelfPermission(Objects.requireNonNull(getActivity()), Manifest.permission.ACCESS_FINE_LOCATION)
!= PackageManager.PERMISSION_GRANTED) {
ActivityCompat.requestPermissions(getActivity(),
new String[]{Manifest.permission.ACCESS_FINE_LOCATION},
0);
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.