如何计算字典中值的比率？

Question

假设我有这样一本字典：

d = {1.0: 11, 2.0: 3, 3.0: 7}

我需要计算每个值与后面的值 (k+1) 的比值，然后将计算出的所有比值之和除以计算出的比值个数，在本例中为 2。如果有兴趣，这是用于计算一个 '分叉点stream 统计数据中的比率'。

预计 output：

• r1 = 11/3 = 3.67
• r2 = 3/7 = 0.43

比率总和 = 3.67 + 0.43 = 4.1 解决方案 = 4.1 / 2 = 2.05

Answer 1

d = {1.0: 11, 2.0: 3, 3.0: 7}

ratio_values = list(d.values())

count = len(ratio_values) - 1
ratio_sum = 0

for i in range(len(ratio_values) - 1):
    #adds the ratio between two consecutive values to the total sum
    ratio_sum += ratio_values[i]/ratio_values[i+1]

print(ratio_sum/count)

Answer 2

import numpy as np

arr = np.array(list(d.values()))
arr

ans = 0
ratios = []
for i in range(1, len(arr)):
    ratios.append(arr[i-1]/arr[i])
ans = sum(ratios)/len(ratios)

Answer 3

d = {1.0: 11, 2.0: 3, 3.0: 7}
d = list(d.values())

ratios = []
solution = 0.0

per = d[0]
for v in d[1:]:
    ratios.append(per/v)
    per = v

solution = sum(ratios)/len(ratios)