[英]python sparql query creating with user input
我正在尝试使用 python 构建 sparql 查询并从用户那里获取一些数据
这是我的代码:
@app.route('/api/v1/getCourseByCode', methods=['GET'])
def api_getCourseByCode():
if 'courseId' in request.args:
courseId = request.args['courseId']
else:
return "Error: No course id provided. Please specify an course id."
onto = get_ontology("https://website/lumiere8.owl")
onto.load()
graph = onto.world.as_rdflib_graph()
query = """PREFIX lumiere: <http://www.smacrs.com/lumiere.owl#>
SELECT ?individual
WHERE { ?individual a lumiere:Course ;
lumiere:Code ?propertyValue .
FILTER(STR(?propertyValue) = {fname})}""".format(fname=courseId)
print("---------------------------------------")
print(query)
course = list(graph.query_owlready(query))
print(course)
return course
我收到以下错误:
查询是这样工作的:
course = list(graph.query_owlready("""PREFIX lumiere: <http://www.smacrs.com/lumiere.owl#>
SELECT ?individual
WHERE { ?individual a lumiere:Course ;
lumiere:Code ?propertyValue .
FILTER(STR(?propertyValue) = "CS101")}
"""))
但问题是我想从 api 方法中获取用户输入
这是我使用的作品%S查询
course=list(graph.query_owlready("""PREFIX lumiere: <http://www.smacrs.com/lumiere.owl#>
SELECT ?individual
WHERE { ?individual a lumiere:Course ;
lumiere:Code ?propertyValue .
FILTER(STR(?propertyValue) = "%s")}
""" %courseId))
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