多维数组排序 - Python

Question

from numpy import *

list = array([["A", 25, 2], ["B", 25, 3], ["C", 10, 1], ["D", 50, 25]])

如何按第二个元素除以第三个元素的降序大小对这个数组进行排序。 所以在这种情况下，正确的安排是：

["A", 25, 2], ["C", 10, 1], ["B", 25, 3], ["D", 50, 25]

Answer 1

import numpy as np

# Let's use a as the variable name so we don't override the list keyword
a = np.array([["A", 25, 2], ["B", 25, 3], ["C", 10, 1], ["D", 50, 25]])

# Need to convert values to int, because they are being casted as string
# in the original array (arrays only support one data type)
key_values = a[:,1].astype(int) / a[:,2].astype(int)

# Use argsort to get a sort index, then reverse the order to make it descending
index_array = np.argsort(key_values)[::-1]  # -1 reverses the order

print(a[index_array])

输出：

[['A' '25' '2']
 ['C' '10' '1']
 ['B' '25' '3']
 ['D' '50' '25']]

Answer 2

你能用熊猫吗？ 如果是这样的话，

import numpy as np
import pandas as pd

df = pd.DataFrame(np.array([["A", 25, 2], ["B", 25, 3], ["C", 10, 1], ["D", 50, 25]]))
df[1] = pd.to_numeric(df[1])
df[2] = pd.to_numeric(df[2])
df[3] = df[1] / df[2]
sorted_list = df.sort_values(by=3, ascending=False).values[:,:3]
print(sorted_list)

array([['A', 25, 2],
       ['C', 10, 1],
       ['B', 25, 3],
       ['D', 50, 25]], dtype=object)

请注意，这里我假设（基于我对问题的理解）您想要根据第 2 列的值除以第 3 列的值进行排序。 如果是这种情况，输出示例将翻转前两个元素（因为 25/2 > 10/1）。