如何排除 8 个字符以下的单词？

Question

我正在编写一个读取行（字典的单词）的程序，我想排除不包含的单词，例如，最少 8 个字符。

我试图在谷歌上搜索，但我没有找到。

这是我想做的那种程序：

with open('words.txt', 'r') as f: 
    lines = f.read().split('\n')   
    lenght = 8
    #and now the part i struggle with
     If lenght under 8:
        exclude it
    else:
        print(goodword)
    

Answer 1

您可以使用len(line)来查找字符串的长度。

with open('words.txt', 'r') as f: 
    lines = f.read().split('\n')   
length = 8
goodwords = [w for w in lines if len(w) >= length]

print(*goodwords, sep='\n')

行goodwords = [...是一个列表goodwords = [... ，可以用标准for loop替换：

goodwords = [] # initiate your list
for word in lines: # evaluate each word
    if len(word) >= length: # word is accepted
        goodwords.append(word)
    # else:
        # no need for an else clause
        # in the event that word has less than 8 letters
        # the code will just continue with the next word