[英]alternative of for loop in R
cell_support_xyz <- function(level, zero)
{
for(i in 1:level[1]){
for(j in 1:level[2]){
for(k in 1:level[3]){
cat("cell (", i, ", ", j, ", ", k,") --> support set = (",
+!(i == zero[1]), ", ", +!(j == zero[2]), ", ", +!(k == zero[3]), ")\n", sep = "")
}
}
}
}
#Example 1
l<-c(2,3,2)
z<-c(1,1,1)
> cell_support_xyz(l,z)
cell (1, 1, 1) --> support set = (0, 0, 0)
cell (1, 1, 2) --> support set = (0, 0, 1)
cell (1, 2, 1) --> support set = (0, 1, 0)
cell (1, 2, 2) --> support set = (0, 1, 1)
cell (1, 3, 1) --> support set = (0, 1, 0)
cell (1, 3, 2) --> support set = (0, 1, 1)
cell (2, 1, 1) --> support set = (1, 0, 0)
cell (2, 1, 2) --> support set = (1, 0, 1)
cell (2, 2, 1) --> support set = (1, 1, 0)
cell (2, 2, 2) --> support set = (1, 1, 1)
cell (2, 3, 1) --> support set = (1, 1, 0)
cell (2, 3, 2) --> support set = (1, 1, 1)
上面的代码工作得很好。 但我想避免for循环。 这里我使用了 3 个 for 循环(因为两个参数向量的长度都是 3)。 如果向量的长度增加或减少,函数将不起作用(我需要相应地调整 for 循环); 这就是为什么我想用一些适用于任何长度的有效替代方法替换 for 循环。 有什么建议吗?
一种删除for
循环并使解决方案对于任何长度输入足够灵活的方法。
我们使用expand.grid
创建所有可能的level
组合,并使用apply
rowwise 创建要打印的字符串。
cell_support_xyz <- function(level, zero) {
tmp <- do.call(expand.grid, lapply(level, seq))
abc <- apply(tmp, 1, function(x)
cat(sprintf('cell (%s) --> support set = (%s)\n',
toString(x), toString(+(x != zero)))))
}
l<-c(2,3,2)
z<-c(1,1,1)
cell_support_xyz(l, z)
#cell (1, 1, 1) --> support set = (0, 0, 0)
#cell (2, 1, 1) --> support set = (1, 0, 0)
#cell (1, 2, 1) --> support set = (0, 1, 0)
#cell (2, 2, 1) --> support set = (1, 1, 0)
#cell (1, 3, 1) --> support set = (0, 1, 0)
#cell (2, 3, 1) --> support set = (1, 1, 0)
#cell (1, 1, 2) --> support set = (0, 0, 1)
#cell (2, 1, 2) --> support set = (1, 0, 1)
#cell (1, 2, 2) --> support set = (0, 1, 1)
#cell (2, 2, 2) --> support set = (1, 1, 1)
#cell (1, 3, 2) --> support set = (0, 1, 1)
#cell (2, 3, 2) --> support set = (1, 1, 1)
您可以分两步完成:
l<-c(2,3,2)
z<-c(1,1,1)
cells <- expand.grid(lapply(l, seq))
t(apply(cells, 1, function(x) 1L*!(x == z)))
cells
包含所有组合。 如果顺序很重要,您可以简单地重新排序:
cells <- dplyr::arrange(cells, Var1, Var2, Var3)
然后,对于每一行( apply(,1,)
),您可以使用==
已经矢量化来将整行与整个z
向量进行比较。
乘以1L
使其成为整数,与+
相同。
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