如何将参数从函数返回到另一个函数？

Question

我目前正在尝试创建一种扑克游戏，如果您输入一个整数（要玩多少轮），然后让人类和计算机根据您输入的整数生成卡片并决定每轮谁获胜。 我的问题是如何将一个参数从一个函数返回到另一个函数？ 我在函数poker()中有 x, y ，我想用它在函数totalwins()进行比较。

import random

Deck = ['Diamond', 'Hearts', 'Jack', 'Spade']
Number = [1,2,3,4,5,6,7,8,9,10,11,12]


def poker(x,y):
    Times = int(input('How many rounds would you like to play: '))
    
    while Times > 0:
        Human = random.choice(Deck)
        Human_value = random.choice(Number)
        Computer = random.choice(Deck)
        Computer_value = random.choice(Number)
        
    
        print('Human: ', Human , Human_value)
        print('Computer: ', Computer, Computer_value)
        
        if Human_value > Computer_value:
            print('Human wins')
            x +=1
        elif Human_value < Computer_value:
            print('Computer wins')
            y += 1
        else:
            print('Tie')

        Times -= 1
poker(0,0)


def totalwins():
    
    if x > y:
        print('Human wins!')
    else:
        print('Computer wins!')
totalwins()

Answer 1

代码很乱，但这里是如何将返回值传递给下一个函数

Deck = ['Diamond', 'Hearts', 'Jack', 'Spade']
Number = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12]


def poker():

    # instead of passing x, y as 0 i am initializing inside
    x = 0
    y = 0

    Times = int(input('How many rounds would you like to play: '))

    while Times > 0:
        Human = random.choice(Deck)
        Human_value = random.choice(Number)
        Computer = random.choice(Deck)
        Computer_value = random.choice(Number)

        print('Human: ', Human, Human_value)
        print('Computer: ', Computer, Computer_value)

        if Human_value > Computer_value:
            print('Human wins')
            x += 1
        elif Human_value < Computer_value:
            print('Computer wins')
            y += 1
        else:
            print('Tie')

        Times -= 1

        # returning x, y to the next funcction
        return x, y


def totalwins():
    x, y = poker()
    if x > y:
        print('Human wins!')
    else:
        print('Computer wins!')


totalwins()

Answer 2

也许是扑克结束时的回报声明？ 就像是：

return (x,y)

然后在调用 poker 时捕获值：

x,y = poker(0,0)

然后更改 totalwins 的参数列表以接受x和y并调用：

totalwins(x,y)

或者你可以将x和y全局，但我不会走那条路

Answer 3

一旦 while 循环在poker函数内部结束total_wins(x,y)您就调用函数total_wins(x,y) 。

由于变量x和y在poker函数内递增，因此应在其中调用函数total_wins ，如下面更正后的代码所示：

import random
Deck = ['Diamond', 'Hearts', 'Jack', 'Spade']
Number = [1,2,3,4,5,6,7,8,9,10,11,12]

def totalwins(x,y):
    if x == y:
      print('It\'s a tie!')
    elif x > y:
        print('Human wins!')
    else:
        print('Computer wins!')

def poker(x,y):
    Times = int(input('How many rounds would you like to play: '))
    
    while Times > 0:
        Human = random.choice(Deck)
        Human_value = random.choice(Number)
        Computer = random.choice(Deck)
        Computer_value = random.choice(Number)
    
        print('Human: ', Human , Human_value)
        print('Computer: ', Computer, Computer_value)
        
        if Human_value > Computer_value:
            print('Human wins')
            x +=1
        elif Human_value < Computer_value:
            print('Computer wins')
            y += 1
        else:
            print('Tie')

        Times -= 1
    totalwins(x,y)
poker(0,0)

• PS：在total_wins函数中也增加了Tie的条件。
• 注意：确保将 total_wins 函数放在 poker 函数之前。