我如何让我的机器人判断给出的数字是高于还是低于答案？ [不和谐.py]

Question

我正在制作一个数字猜谜游戏，我想知道如何让它告诉您您的答案是高于还是低于答案？ 到目前为止，这是我的代码：

async def number(ctx):
    await ctx.send('I\'m thinking of a number from one to ten. Try to guess which number!')
    number = random.randint(1, 10)
    answer = await client.wait_for('message', check=lambda message: message.author == ctx.author and message != "")
    answer = answer.content

    loop_counter = 0
    while answer.lower() != number:
        loop_counter += 1
        if loop_counter >= 2:
            await ctx.send(f'sorry dude, the correct number was {number}')
            break
        await ctx.send('Incorrect, try again')
        answer = await client.wait_for('message', check=lambda message: message.author == ctx.author and message != "")
        answer = answer.content

        if answer.lower() == number:
            "[testing]" ```
Thanks!

Answer 1

在while循环中，您也可以添加一个if-else循环。

while answer.lower() != number:
    if answer.lower()<number:
        #Do things if the number is lower
    else: 
        #Do things if the number is higher
    loop_counter += 1
    if loop_counter >= 2:
        await ctx.send(f'sorry dude, the correct number was {number}')
        break

注意：虽然通常当你检查一个数字是否更高/更低时你不能使用else因为数字可能相等，看到它们是否相等循环不会开始，你可以在这里使用else

Answer 2

首先， if answer.lower() == number:你不能这样做，因为answer是一个str object 但number是一个integer 。 所以你不能比较它们。 而且你也不必做wait_for 2 次。 您也可以将它添加到 while 循环中。 你可以使用这个：

@client.command()
async def number(ctx):
    await ctx.send('I\'m thinking of a number from one to ten. Try to guess which number!')
    number = random.randint(1, 10)
    loop_counter = 0
    while loop_counter < 2:
        anwser = client.wait_for('message', check=lambda message: message.author == ctx.author)
        try:
            answ = int(answer.content) # here it will try to return answer to a integer.
        except ValueError:
            await ctx.send('Please just type number.') # if it's not integer, then it will pass and send a warning.
            pass
        if answ == number:
            await ctx.send('You found the number.') # if user founds the answer, it will send a message and ends the loop.
            return
        else:
            await ctx.send('Sorry, wrong answer. Answer is higher.') if number-answ<0 else await ctx.send('Sorry, wrong answer. Answer is lower.')
            loop_counter += 1
    await ctx.send(f"Sorry, you couldn't find the answer. Answer was {number}")