尝试根据用户输入从嵌套字典中获取特定值

Question

我正在尝试根据用户输入从嵌套字典中获取特定值。 到目前为止，我拥有的代码返回“无无”。 任何帮助将不胜感激！

customer_dict = {
    "ctmr1" : {
        "Fname" : "John",
        "Lname" : "Smith",
        "Username" : "smithj",
        "Password" : "123"
    },
    "ctmr2" : {
        "Fname" : "Anita",
        "Lname" : "Job",
        "Username" : "joba",
        "Password" : "456"
    }
}

usrnm = input("Enter username: ")
psw = input("Enter password: ")

u = customer_dict.get("Username",{}).get(usrnm)
p = customer_dict.get("Password", {}).get(psw)

print (u,p)

if usrnm != u or psw != p:
    print("Wrong credentials")
else:
    print("Welcome!")

Answer 1

您正在尝试通过第一级的用户名获取字典，但是嵌套字典中的用户名您需要先获取嵌套字典，

尝试这样的功能，首先获取用户字典

def get_user(users,username):
    for user in users.values():
        if user['Username'] == username:
            return user

那么你可以

uer = get_user(customer_dict,usrnm)

但我建议重新排列字典，以便将用户名作为键

customer_dict = {
    "smithj" : {
        "Fname" : "John",
        "Lname" : "Smith",
        "Password" : "123"
    },
    ...
}

所以你可以做的不是这一切

customer_dict.get('username')

Answer 2

这将解决您的问题

usrnm = input("Enter username: ")
psw = input("Enter password: ")

found_flag = False
for ctmr in customer_dict:
  u = customer_dict[ctmr].get("Username")
  p = customer_dict[ctmr].get("Password")
  if usrnm != u or psw != p:
    continue
  else:
    found_flag = True
    break

if found_flag == True:
  print('Welcome')
else:
  print('Wrong Credentials')