[英]How to continue a try/except
我目前正在学习“尝试”和“除外”概念,我有一个小问题。
def sum_file():
try:
with open("text.txt") as entry:
result = 0
try:
for line in entry:
result += int(line.strip())
print(result)
except ValueError:
print("Non-integer number entered")
except:
print("Non-existent file.")
文件的每一行都是一个数字,一些数字是整数,其他数字是浮点数。 代码正确地对第一个整数求和,但是当第一个浮点数出现时,程序停止,当还有更多行时。 如何修改代码使其继续操作?
您需要将第二个try
块放入循环中:
def sum_file():
try:
with open("text.txt") as entry:
result = 0
for line in entry:
try:
result += int(line.strip())
print(result)
except ValueError:
print("Non-integer number entered")
except:
print("Non-existent file.")
或者你可以使用re来帮助你。
re.match(r".*\\D+.*", line)
匹配任何包含一个或多个非[0-9] 字符的行
from io import StringIO
import re
text_txt = """\
3.1
123
4 b 5 6
7.2
c'] ? 9
10
"""
def sum_file():
with StringIO(text_txt) as f:
result_list = []
for line in [_.strip() for _ in f]:
m = re.match(r".*\D+.*", line)
print("Non-integer number entered") if m else (print(line), result_list.append(int(line)))
print(f'result: {sum(result_list)}') if result_list else None
sum_file()
输出
Non-integer number entered
123
Non-integer number entered
Non-integer number entered
Non-integer number entered
10
result: 133
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