如何将包含两列字符串的txt拆分为列表？

Question

我需要一些简单的帮助，我尝试了不同的代码。 但没有任何工作正常。

我有一个 .txt 文件，其中两列用空格分隔。 该文件如下所示：

我想将这些字符串拆分为一个列表以获得以下结果：

my_list=['1', 'abacaxi','1','abalo','1','abalos', '0', 'abacate']

我怎样才能做到这一点？ 下面的代码运行，但结果不是我需要的。

import os
import io
import sys
from pathlib import Path

while True:
    try:
        file_to_open =Path(input("Please, insert your file path: "))
        with open(file_to_open,'r', encoding="utf-8") as f:
            words = f.read().lower()
            break         
    except FileNotFoundError:
        print("\nFile not found. Better try again")
    except IsADirectoryError:
        print("\nIncorrect Directory path.Try again")


print('total number of words + articles: ', len(words))
corpus=words.split(' ')
print(corpus[0:20])

Answer 1

这里是 go，

with open(file_to_open,'r', encoding="utf-8") as f:
    words = f.read().lower()

#Split the lines and join them into one line, and single spaces between them
words = " ".join(words.split(sep='\n'))

#remove double spaces with single space
    while "  " in words:
        words = words.replace("  ", " ")
#Split the line silimiter ' ' i.e. space into a list
word_li = " ".join(words.split(sep=' '))