[英]Pandas- locate a value based on logical statements
我正在将此数据集用于项目。 我试图找到数据集 34 天持续时间内每个逆变器的总产量(基本上使用每个逆变器可用的最终值和初始值)。 我已经能够使用pd.unique()
获得逆变器列表(每个太阳能发电厂有 22 个逆变器。
我无法查询每个逆变器的total_yield
数据。 这是我尝试过的:
def get_yields(arr: np.ndarray, df:pd.core.frame.DataFrame) -> np.ndarray:
delta = np.zeros(len(arr))
index =0
for i in arr:
initial = df.loc[df["DATE_TIME"]=="15-05-2020 02:00"]
initial = initial.loc[initial["INVERTER_ID"]==i]
initial.reset_index(inplace=True,drop=True)
initial = initial.at[0,"TOTAL_YIELD"]
final = df.loc[(df["DATE_TIME"]=="17-06-2020 23:45")]
final = final.loc[final["INVERTER_ID"]==i]
final.reset_index(inplace=True, drop=True)
final = final.at[0,"TOTAL_YIELD"]
delta[index] = final - initial
index = index + 1
return delta
参考: arr
为逆变器数组,如下所列。 df
是每个工厂的 dataframe 代。
问题是并非每个逆变器都有每个间隔的数据点。 这使得该 function 仅适用于第一工厂的逆变器,而不适用于第二工厂。
我的第二种方法是先通过逆变器进行过滤,然后获取第一个和最后一个数据点。 但是我得到一个错误-'Series 'Series' objects are mutable, thus they cannot be hashed
这里是到目前为止的代码:
def get_yields2(arr: np.ndarray, df: pd.core.frame.DataFrame) -> np.ndarry:
delta = np.zeros(len(arr))
index = 0
for i in arr:
initial = df.loc(df["INVERTER_ID"] == i)
index += 1
break
return delta
供参考的工厂 1 逆变器列表(标记为SOURCE_KEY
):
['1BY6WEcLGh8j5v7' '1IF53ai7Xc0U56Y' '3PZuoBAID5Wc2HD' '7JYdWkrLSPkdwr4'
'McdE0feGgRqW7Ca' 'VHMLBKoKgIrUVDU' 'WRmjgnKYAwPKWDb' 'ZnxXDlPa8U1GXgE'
'ZoEaEvLYb1n2sOq' 'adLQvlD726eNBSB' 'bvBOhCH3iADSZry' 'iCRJl6heRkivqQ3'
'ih0vzX44oOqAx2f' 'pkci93gMrogZuBj' 'rGa61gmuvPhdLxV' 'sjndEbLyjtCKgGv'
'uHbuxQJl8lW7ozc' 'wCURE6d3bPkepu2' 'z9Y9gH1T5YWrNuG' 'zBIq5rxdHJRwDNY'
'zVJPv84UY57bAof' 'YxYtjZvoooNbGkE']
2厂逆变器列表:
['4UPUqMRk7TRMgml' '81aHJ1q11NBPMrL' '9kRcWv60rDACzjR' 'Et9kgGMDl729KT4'
'IQ2d7wF4YD8zU1Q' 'LYwnQax7tkwH5Cb' 'LlT2YUhhzqhg5Sw' 'Mx2yZCDsyf6DPfv'
'NgDl19wMapZy17u' 'PeE6FRyGXUgsRhN' 'Qf4GUc1pJu5T6c6' 'Quc1TzYxW2pYoWX'
'V94E5Ben1TlhnDV' 'WcxssY2VbP4hApt' 'mqwcsP2rE7J0TFp' 'oZ35aAeoifZaQzV'
'oZZkBaNadn6DNKz' 'q49J1IKaHRwDQnt' 'rrq4fwE8jgrTyWY' 'vOuJvMaM2sgwLmb'
'xMbIugepa2P7lBB' 'xoJJ8DcxJEcupym']
非常感谢。
我无法下载数据集来测试这一点。 收到“To May Requests”错误。
但是,您应该能够使用groupby
来做到这一点。
import pandas as pd
result = df.groupby('INVERTER_ID')['TOTAL_YIELD'].agg(['max','min'])
result['delta'] = result['max']-result['min']
print(result[['delta']])
因此,如果我理解这一点,您想要的是从TOTAL_YIELD
5-05-2020 02:00
开始到17-06-2020 23:45
结束的时间段开始时每个逆变器的 TOTAL_YIELD 。 尝试这个:
# enumerate lets you have an index value along with iterating through the array
for i, code in enumerate(arr):
# to filter the info to between the two dates, but not necessarily assuming that
# each inverter's data starts and ends at each date
inverter_df = df.loc[df['DATE_TIME'] >= pd.to_datetime('15-05-2020 02:00:00')]
inverter_df = inverter_df.loc[inverter_df['DATE_TIME'] <= pd.to_datetime('17-06-2020
23:45:00')]
inverter_df = inverter_df.loc[inverter_df["INVERTER_ID"]==code]]
# sort by date
inverter_df.sort_values(by='DATE_TIME', inplace= True)
# grab TOTAL_YIELD at the first available date
initial = inverter_df['TOTAL_YIELD'].iloc[0]
# grab TOTAL_YIELD at the last available date
final = inverter_df['TOTAL_YIELD'].iloc[-1]
delta[index] = final - initial
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