[英]Python Socket Server receives gibberish text files, after client sends an text file
[英]Is there a way to set up a python socket so that the server only sends when the client asks for an updated value?
我试图从一个 python 脚本中获取一个值到另一个脚本中。 第一个脚本必须一直运行,接收脚本不能一直运行,需要从第一个获取最新的值。
现在脚本几乎没有 function 。 但由于接收方运行速度比发送方慢,因此积压了 forms。 如果发件人没有新数据,我还需要一种方法来使用先前的值继续第二个脚本。 否则,程序会在发送方停止时挂起。
import socket
sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
tabletPressure = "Value constantly updates while pen is pressed, value is between 0,4096"
while True:
if pen_pressed:
intValue = int(tabletPressure)
bytesValue = (intValue).to_bytes(4, byteorder="little")
sock.sendto(bytesValue,("0.0.0.0", 33335))
接收脚本如下所示
import socket
import time
dataBus = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
dataBus.bind(('0.0.0.0', 33335))
def modal(self, context, event):
if event.type in {'RIGHTMOUSE', 'ESC'}:
self.cancel(context)
self.dataBus.close()
return {'CANCELLED'}
if event.type == 'MOUSEMOVE':
data, addr = dataBus.recvfrom(4)
print(int.from_bytes(data, byteorder="little"))
我真的很感激任何帮助! 谢谢!
将服务器设置为仅在收到消息时才发送消息。 例子:
服务器.py
from socket import *
from threading import Thread
from time import sleep
s = socket(AF_INET,SOCK_DGRAM)
s.bind(('',5000))
counter = 0
def datagram_server():
while True:
data,addr = s.recvfrom(4096) # receive any message
s.sendto(counter.to_bytes(4,'little'),addr) # respond to client address
Thread(target=datagram_server,daemon=True).start()
while True:
sleep(.5)
counter += 1 # constantly updating value
客户端.py
from socket import *
from time import sleep
s = socket(AF_INET,SOCK_DGRAM)
server = 'localhost',5000
ping = b'' # message content doesn't matter
def get_latest_counter():
s.sendto(ping,server) # ping server to get a response
data,addr = s.recvfrom(4) # get the response
return int.from_bytes(data,'little')
while True:
print(get_latest_counter())
sleep(1)
Output:
5
7
9
11
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