如何修复 Python 代码中的未绑定本地错误？

Question

你能帮我修好这条鳕鱼吗？ 在我像在 30 秒后运行它之后，它显示“UnboundLocalError：分配前引用的局部变量'命令'”你能帮我解决它吗？ 我尝试了许多关于如何修复此错误的教程，但我做不到。

import speech_recognition as sr
import pyttsx3
import pywhatkit
import datetime
import pyjokes

listener = sr.Recognizer()
engine = pyttsx3.init()
voices = engine.getProperty('voices')
engine.setProperty('voice', voices[1].id)


def talk(text):
    engine.say(text)
    engine.runAndWait()


def take_command():
    try:
        with sr.Microphone() as source:
            print('listening...')
            voice = listener.listen(source)
            command = listener.recognize_google(voice)
            command = command.lower()
            if 'idiot' in command:
                command = command.replace('idiot', '')
                print(command)
    except:
        pass

    return command

def run_idiot():
    command = take_command()
    print(command)
    if 'play' in command:
        song = command.replace('play', '')
        talk('playing ' + song)
        pywhatkit.playonyt(song)
    elif 'time' in command:
        time = datetime.datetime.now().strftime('%I:%M %p')
        print(time)
        talk(time)
    
    else:
        talk('Please say the command again.')


while True:
    run_idiot()

Answer 1

如果发生异常，您将没有command的定义，因此返回它会导致无界本地错误。 所以你需要先声明它：

def take_command():
    # declare 'command' variable outside try-except
    command = ""
    try:
        with sr.Microphone() as source:
            print('listening...')
            voice = listener.listen(source)
            command = listener.recognize_google(voice)
            command = command.lower()
            if 'idiot' in command:
                command = command.replace('idiot', '')
                print(command)
    except:
        pass

    return command