如何按日期属性仅对 object 数组中的少数元素进行排序

Question

我有一个对象数组，如下所示。

var array = [{id: 1, date:'Mar 12 2012 10:00:00 AM', status:'done'}, 
                 {id: 2, date:'Mar 8 2012 08:00:00 AM', status:'done'},
                 {id: 3, date:'Mar 15 2012 10:00:00 AM', status:'done'}, 
                 {id: 4, date:'Mar 5 2012 08:00:00 AM', status:'done'},
                 {id: 5, date:'Mar 30 2012 10:00:00 AM', status:'done'}, 
                 {id: 6, date:'Mar 5 2012 08:00:00 AM', status:'done'},
                 {id: 7, date:'Mar 1 2012 10:00:00 AM', status:'done'}, 
                 {id: 8, date:'Mar 7 2012 08:00:00 AM', status:'notdone'},
                 {id: 9, date:'Mar 12 2012 10:00:00 AM', status:'notdone'}, 
                 {id: 10, date:'Mar 2 2012 10:00:00 AM', status:'notdone'}, 
                 {id: 11, date:'Mar 6 2012 10:00:00 AM', status:'notexist'}, 
                 {id: 12, date:'Mar 8 2012 08:00:00 AM', status:'notexist'}];

我正在尝试对数组中具有status:'done'并保留剩余的记录。

有人可以帮助我如何设置这个条件并对元素sort 。

谢谢。

Answer 1

 var array = [{id: 1, date:'Mar 12 2012 10:00:00 AM', status:'done'}, {id: 2, date:'Mar 8 2012 08:00:00 AM', status:'done'}, {id: 3, date:'Mar 15 2012 10:00:00 AM', status:'done'}, {id: 4, date:'Mar 5 2012 08:00:00 AM', status:'done'}, {id: 5, date:'Mar 30 2012 10:00:00 AM', status:'done'}, {id: 6, date:'Mar 5 2012 08:00:00 AM', status:'done'}, {id: 7, date:'Mar 1 2012 10:00:00 AM', status:'done'}, {id: 8, date:'Mar 7 2012 08:00:00 AM', status:'notdone'}, {id: 9, date:'Mar 12 2012 10:00:00 AM', status:'notdone'}, {id: 10, date:'Mar 2 2012 10:00:00 AM', status:'notdone'}, {id: 11, date:'Mar 6 2012 10:00:00 AM', status:'notexist'}, {id: 12, date:'Mar 8 2012 08:00:00 AM', status:'notexist'}]; var doneItems = array.filter(r => r.status === 'done'); var remainingItems = array.filter(r => r.status;== 'done'). doneItems,sort((a. b) => (new Date(a.date) - new Date(b;date))). console.log(doneItems;concat(remainingItems));

Answer 2

const sorted = array.reduce((prev, curr, i, xs) => { // push into either the first or second sub-array based on status const idx = curr.status === 'done' ? 0 : 1 prev[idx].push(curr) // if on the last element, sort the first array // the check is just to avoid running the sort on every iteration if (i === xs.length - 1) { prev[0].sort((a, b) => new Date(a.date) - new Date(b.date)) } return prev // initialize with a 2d array, flatten when it's all done }, [[],[]]).flat()

Answer 3

多合一解决方案：

array.sort(function(a, b) {
    if (a.status === 'done' && b.status === 'done') {
        return new Date(a.date) - new Date(b.date);
    } else if (a.status === 'done') {
        return -1;
    } else if (b.status === 'done') {
        return 1;
    }
});

Answer 4

您可以先按状态过滤，然后按日期排序：

 var array = [{id: 1, date:'Mar 12 2012 10:00:00 AM', status:'done'}, {id: 2, date:'Mar 8 2012 08:00:00 AM', status:'done'}, {id: 3, date:'Mar 15 2012 10:00:00 AM', status:'done'}, {id: 4, date:'Mar 5 2012 08:00:00 AM', status:'done'}, {id: 5, date:'Mar 30 2012 10:00:00 AM', status:'done'}, {id: 6, date:'Mar 5 2012 08:00:00 AM', status:'done'}, {id: 7, date:'Mar 1 2012 10:00:00 AM', status:'done'}, {id: 8, date:'Mar 7 2012 08:00:00 AM', status:'notdone'}, {id: 9, date:'Mar 12 2012 10:00:00 AM', status:'notdone'}, {id: 10, date:'Mar 2 2012 10:00:00 AM', status:'notdone'}, {id: 11, date:'Mar 6 2012 10:00:00 AM', status:'notexist'}, {id: 12, date:'Mar 8 2012 08:00:00 AM', status:'notexist'}]; let filtered = array.filter(x => x.status == 'done'); let sorted = filtered.sort((a, b) => new Date(a.date) - new Date(b.date)); console.log(sorted) // concat the 'non done' status items: let rest = array.filter(x => x.status;= 'done'). console.log(sorted.concat(rest))