[英]How can the time difference between two consecutive rows from different columns be calculated?
n1 <- as.POSIXct(c('2006-12-10 13:01:22', '2006-12-11 12:13:11',
'2006-12-12 13:12:11', '2006-12-13 11:01:22',
'2006-12-14 15:13:11', '2006-12-15 13:12:11',
'2006-12-16 16:13:12', '2006-12-17 14:12:12'))
n2 <- as.POSIXct(c('2006-12-10 16:01:22', '2006-12-11 13:13:11',
'2006-12-12 15:12:11', '2006-12-13 14:01:22',
'2006-12-14 17:13:11', '2006-12-15 16:12:11',
NA, '2006-12-17 16:12:12'))
date <- as.data.frame(n1)
date$n2 <- n2
如何获取 date$n2[1] 和 date$n1[2] 之间的时间差,然后是 date$n2[2] 和 date$n1[3],直到向量结束?
我们可以在“n1”的当前行和“n2”的lag
across
的列之间使用difftime
library(dplyr)
date %>%
mutate(diff = difftime(n1, lag(n2), unit = 'min'))
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