Function 接受一串字母，从有效单词列表中输出单词列表，然后找到拼字游戏得分最高的单词

Question

我一直在尝试构建一个 function，它接受一串字母，从有效单词列表中输出单词列表，然后从该列表中找到拼字游戏得分最高的单词

我设计了一个 function 从字符串中输出所有可能的单词，一个 function 从单词列表中计算拼字游戏分数，一个 function 输出最高分数

但是，我正在努力：

1. 将这三者结合起来（计算 output 列表中可能得分最高的）和
2. 返回一个包含所有可能单词的列表，第二个单词生成 function，目前，它在单独的列表中输出单词

计算拼字游戏分数的 Function

def scrabble_score(word):
    total = 0 # Create score var
    for i in word: # Loop through given word
        total += score[i.lower()] #Lookup in dict, add total
    return totaldef charCount(word): 
    dict = {} 
    for i in word: 
        dict[i] = dict.get(i, 0) + 1
    return dict

Function 输出可能的话

def possible_words(lwords, charSet): 
    for word in lwords: 
        flag = 1
        chars = charCount(word) 
        for key in chars: 
            if key not in charSet: 
                flag = 0
            elif charSet.count(key) != chars[key]: 
                    flag = 0        #for word in word_list:
        if flag == 1: 
            #word_value_dict = {}
            firstList = []
            #word_value_dict[word] = get_word_value(word, letter_values)
            firstList.append(word)
            #return word_value_dict
            print(scrabble_score(word), (word))
            print(firstList)if __name__ == "__main__": 
    input = ['goo', 'bat', 'me', 'eat', 'goal', 'boy', 'run'] 
    charSet = ['e', 'o', 'b', 'a', 'm', 'g', 'l', 'b'] 
    possible_words(input, charSet) 

Function 可以从列表中找到得分最高的单词

 def score(word):


        dic =  {"a": 1, "c": 3, "b": 3, "e": 1, "d": 2, "g": 2, 
          "f": 4, "i": 1, "h": 4, "k": 5, "j": 8, "m": 3, 
          "l": 1, "o": 1, "n": 1, "q": 10, "p": 3, "s": 1, 
          "r": 1, "u": 1, "t": 1, "w": 4, "v": 4, "y": 4, 
          "x": 8, "z": 10}
        total = 0
        for char in word:
            total += dic.get(char.upper(), 0)
        return total
    #return highest score
    def best(lista):
        return max(lista, key=score)best(['goo', 'bat', 'me', 'eat', 'run'])

当前 Output：

4 me
['me']
5 goal
['goal']

所需的 output：所有可能单词的列表

['me', 'goal']

或者一个字典（或类似结构），可能的词作为键，分数作为值

{'me':4, 'goal':5]

AND 得分最高的单词

'goal':5

我需要一种从第一个 function 返回列表的方法，并将两者结合起来以找到该列表中的最高分

保持好状况

Answer 1

您的 function 定义中有一些错误。 我已经复制了下面的更正版本，并在我修改某些内容的地方添加了注释：

def scrabble_score(word):
    total = 0
    for i in word: 
        total += score(i.lower()) # Changed square brackets to normal brackets
    return total 

def charCount(word): 
    dict = {} 
    for i in word: 
        dict[i] = dict.get(i, 0) + 1
    return dict

def score(word):
    dic =  {"a": 1, "c": 3, "b": 3, "e": 1, "d": 2, "g": 2, 
      "f": 4, "i": 1, "h": 4, "k": 5, "j": 8, "m": 3, 
      "l": 1, "o": 1, "n": 1, "q": 10, "p": 3, "s": 1, 
      "r": 1, "u": 1, "t": 1, "w": 4, "v": 4, "y": 4, 
      "x": 8, "z": 10}
    total = 0
    for char in word:
        total += dic.get(char.lower(), 0) # Change .upper() to .lower() or else it will return only zero
    return total 

def possible_words(lwords, charSet): 
    firstList = {} # Made this a dictionary instead of list
    
    for word in lwords: 
        flag = 1
        chars = charCount(word) 
        for key in chars: 
            if key not in charSet: 
                flag = 0
            elif charSet.count(key) != chars[key]: 
                    flag = 0       
        if flag == 1: 
            firstList[word] = scrabble_score(word) # Adding to the dictionary
    print(firstList)
    best(firstList)

def best(lista):
        print("Best word is '{}' with score {}".format(max(lista, key=score), lista[max(lista, key=score)])) # Changed as per requirements

使用上述 function 定义和以下输入：

input_words = ['goo', 'bat', 'me', 'eat', 'goal', 'boy', 'run'] 
charSet = ['e', 'o', 'b', 'a', 'm', 'g', 'l', 'b'] 

我的 output for possible_words(input_words, charSet)如下：

{'me': 4, 'goal': 5}
Best word is 'goal' with score 5

，这是所希望的。