如何在不更改顺序的情况下比较 python 中的两个列表

Question

我想比较 list a和 list b并找到共同的元素，但结果列表应该具有 list a的顺序。

a = ['apple','ora','bab','ooo']
b = ['ooo','nnn','apple','ora']
c = set(a) & set(b)
print(c)
set(['ooo', 'apple', 'ora'])

我期望的结果是['apple','ora','ooo']列表中a顺序

Answer 1

a = ['apple','ora','bab','ooo']
b = ['ooo','nnn','apple','ora']
common = [x for x in a if x in b]
print(common)
# ['apple', 'ora', 'ooo']