shell 中的字符串操作在一行中

Question

我正在使用以下脚本

list=kmakalas@gmail.com;kmakalas@gmail.com;kmakalas@gmail.com;

对于上述我想提取

r=kmakalas,r=kmakalas,r=kmakalas

为此，我使用了以下 shell 操作

rev_list="r=${list//@gmail.com;/r=}

以上给了我

r=kmakalas,r=kmakalas,r=kmakalas,r=

得到r=kmakalas,r=kmakalas,r=kmakalas

我用rev2="${rev_list%,r=}"

是否有可能在单行命令中执行

Answer 1

使用 GNU awk：

awk -F '[=;]' '{ for(i=2;i<NF;i++) { split($i,map,"@");printf i==(NF-1)?"r="map[1]:"r="map[1]"," } printf "\n" }' <<< "$list"

解释：

awk -F '[=;]' '{                                                     # Set the field delimiter to "=" or ";"
                  for(i=2;i<NF;i++) { 
                      split($i,map,"@");                             # Loop through each field and split the field/address into an array map using "@" as the delimiter
                      printf i==(NF-1)?"r="map[1]:"r="map[1]","      # Print "r=" along with the "@" prefix
                  } 
                  printf "\n" 
                }' <<< "$list"