如何应对 csv 文件列中出现的字符串

Question

我在该文件中有一个 csv 文件，我需要对抗字符串的出现。

例如这是一个示例文件

column_A
Abhi
Spidy
Abhi
Max

所以在上面的 csv 文件中，我需要遵循 output：

output:
Abhi 2
Spidy 1
Max 1

嗨已经试过这个

import csv
import collections

data = collections.Counter()
print(data)
with open('file.csv') as input_file:
    for row in csv.reader(input_file, delimiter=';'):
        data[row[1]] += 1

print('%s' % data['columnA'])
print(data.most_common())

Answer 1

嘿，我看到你是用计数器做的，我用 pandas 只是为了读取 csv 文件：

dict_final = {}
list_intermed = []
df = pd.read_csv('test.csv')
for i in df.A:
    if i in list_intermed:
        dict_final[i] += 1
    else:
        dict_final[i] = 1
        list_intermed.append(i)
print(dict_final)

这将以字典的形式给出 output

---

仅使用 CSV 模块：

import csv
list1 = []
final_dict = {}
list2 = []
with open('test.csv', newline='') as csvfile:
     csv_obj = csv.reader(csvfile, delimiter=',')
     for row in csv_obj:
        list1.append(', '.join(row).split()) #so we get a list of all rows
for i in list1[1:]: #excluding the first row as those are column names
    if i[0][:-1] in list2: #i[0][:-1] takes the rows first element till the second last character the reason we take second last character is so that we don't include a comma that comes in the list items (rest of the code is same)
        final_dict[i[0][:-1]] += 1
    else:
        final_dict[i[0][:-1]] = 1
        list2.append(i[0][:-1])