为游戏中的功能插入计数器。 （在整个运行过程中调用了多少次 function）

Question

import random


def first_player_chance():
    p1 = random.randint(1, 10)
    p2 = random.randint(1, 10)
    if p1 != p2:
        print(p1, p2)
        second_player_chance()

    else:
        print(p1, p2)
        return print("First player won!")


def second_player_chance():
    p1 = random.randint(1, 10)
    p2 = random.randint(1, 10)
    if p1 != p2:
        print(p1, p2)
        first_player_chance()

    else:
        print(p1, p2)
        return print("Second player won!")


first_player_chance()

这个游戏是一种 1 到 10 的机会游戏。 如果第一次尝试都得到相同的数字，则玩家一获胜。 如果他没有获胜，玩家 2 就有机会。 该程序工作并打印所有尝试的游戏。 但我希望 output 类似于：“第一个玩家在 X 次尝试后获胜！”

我如何在这个游戏中实现计数器？ 一个简单的计数器 += 1 不起作用。

Answer 1

您可以使用一个简单的 function 属性来实现它：

import random


def first_player_chance():
    first_player_chance.called += 1  # increment called count
    p1 = random.randint(1, 10)
    p2 = random.randint(1, 10)
    if p1 != p2:
        print(p1, p2)
        second_player_chance()
    else:
        print(p1, p2)
        return print(f"First player won after {first_player_chance.called} rounds!")


def second_player_chance():
    second_player_chance.called += 1
    p1 = random.randint(1, 10)
    p2 = random.randint(1, 10)
    if p1 != p2:
        print(p1, p2)
        first_player_chance()

    else:
        print(p1, p2)
        return print(f"Second player won after {second_player_chance.called} rounds!")

first_player_chance.called = 0  # initialize count for the functions
second_player_chance.called = 0

first_player_chance()

哪个输出：

4 5
5 8
3 1
9 7
10 7
2 1
5 7
5 6
6 2
7 8
4 8
5 6
10 9
3 3
Second player won after 7 rounds!

这可能是您正在寻找的。

请记住，可以通过使用装饰器添加计数器来大量清理代码。

Answer 2

import random

count = 0


def first_player_chance():
    global count
    count += 1
    p1 = random.randint(1, 10)
    p2 = random.randint(1, 10)
    if p1 != p2:
        print(p1, p2)
        second_player_chance()

    else:
        print(p1, p2)
        return print("First player won!")


def second_player_chance():
    global count
    count += 1
    p1 = random.randint(1, 10)
    p2 = random.randint(1, 10)
    if p1 != p2:
        print(p1, p2)
        first_player_chance()

    else:
        print(p1, p2)
        return print("Second player won!")


first_player_chance()
print('count: ', count)

output：

9 8
3 2
1 1
First player won!
count: 3