[英]Nesting Try-Except statements to dim lights and then eventually shut them off
在一段时间没有移动后,我试图调暗灯光,然后在另一段时间后最终将它们完全关闭。 我面临的问题是,当它关闭时,它应该只能选择再次打开,而不是从关闭状态随机变暗。 下面的代码:
async def main(self):
while True:
try:
await asyncio.wait_for(self.movement_detected(), timeout=10)
except asyncio.TimeoutError:
state_off = {"state": "off"}
state_dim = {"brightness":50, "state": "ON"}
print('TIMEOUT...DIMMING ' + topic)
async with Client(self.broker) as client:
await client.publish(topic, orjson.dumps(state_dim))
try:
await asyncio.wait_for(self.movement_detected(), timeout=10)
except asyncio.TimeoutError:
print('TIMEOUT...TURNING OFF ' + topic)
async with Client(self.broker) as client:
await client.publish(topic, orjson.dumps(state_off))
当我运行它时,我得到:
ON
ON
ON
TIMEOUT...DIMMING /light
TIMEOUT...TURNING OFF /light
TIMEOUT...DIMMING /light
TIMEOUT...TURNING OFF /light
TIMEOUT...DIMMING /light
TIMEOUT...TURNING OFF /light
TIMEOUT...DIMMING /light
这意味着我假设意味着我搞砸了 try-except 语句,有人知道解决方法吗?
自己找到了一个解决方法,不认为它是最美观的,但它似乎是 function。
async def main(self):
count = 0
while True:
if count == 1:
try:
await asyncio.wait_for(self.movement_detected(), timeout=60)
count = 0
except asyncio.TimeoutError:
print('TIMEOUT...TURNING OFF ' + topic)
count = 1
async with Client(self.broker) as client:
await client.publish(topic, orjson.dumps(state_off))
else:
try:
await asyncio.wait_for(self.movement_detected(), timeout=900)
count = 0
except asyncio.TimeoutError:
count = 1
state_off = {"state": "off"}
state_dim = {"brightness":50, "state": "ON"}
print('TIMEOUT...DIMMING ' + topic)
async with Client(self.broker) as client:
await client.publish(topic, orjson.dumps(state_dim))
这可以防止它从关闭状态变暗,它只能从开启状态变暗。
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