[英]How to match/search for a specific pattern but not having another specific pattern?
我需要匹配一个模式not check
一个更大的字符串。
bigger_string = '<some words and> do not check <some other words>'
但在那之后它不应该有一个数字。 所以, not check <some words>
应该匹配但not check 67 <some words>
不应该匹配。 我试过这些:
re.findall(re.compile(r'not\s*check\s*\D*', re.I), bigger_string)
re.findall(re.compile(r'not\s*check\s*[^0-9]*', re.I), bigger_string)
它不起作用。 这总是返回一个匹配。
\D*
in not\s*check\s*\D*
表示匹配到第一个数字,如果前面没有数字,则不匹配。
利用
\bnot\s+check\b(?!\s*\d)\D*
见证明。
解释
--------------------------------------------------------------------------------
\b the boundary between a word char (\w) and
something that is not a word char
--------------------------------------------------------------------------------
not 'not'
--------------------------------------------------------------------------------
\s+ whitespace (\n, \r, \t, \f, and " ") (1 or
more times (matching the most amount
possible))
--------------------------------------------------------------------------------
check 'check'
--------------------------------------------------------------------------------
\b the boundary between a word char (\w) and
something that is not a word char
--------------------------------------------------------------------------------
(?! look ahead to see if there is not:
--------------------------------------------------------------------------------
\s* whitespace (\n, \r, \t, \f, and " ") (0
or more times (matching the most amount
possible))
--------------------------------------------------------------------------------
\d digits (0-9)
--------------------------------------------------------------------------------
) end of look-ahead
--------------------------------------------------------------------------------
\D* non-digits (all but 0-9) (0 or more times
(matching the most amount possible))
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