[英]Counting tokenized words in data frame with pandas ( python)
我在 Python 的数据框中创建了一个标记化数据(文本)
我只想计算标记化数据并输出显示标记化数据中每个元素的重复频率。
这是我用来创建标记化数据的代码:
import numpy as np
import pandas as pd
import matplotlib.pyplot as plt
import re
def tokenize(txt):
tokens = re.split('\W+', txt)
return tokens
Complains['clean_text_tokenized'] = Complains['clean text'].apply(lambda x: tokenize(x.lower()))
# Complains['clean text'] is the original file of the data
Complains['clean_text_tokenized'].head(10)
这是标记化数据的输出
0 [comcast, cable, internet, speeds]
1 [payment, disappear, service, got, disconnected]
2 [speed, and, service]
3 [comcast, imposed, a, new, usage, cap, of, 300...
4 [comcast, not, working, and, no, service, to, ...
5 [isp, charging, for, arbitrary, data, limits, ...
6 [throttling, service, and, unreasonable, data,...
7 [comcast, refuses, to, help, troubleshoot, and...
8 [comcast, extended, outages]
9 [comcast, raising, prices, and, not, being, av...
Name: clean_text_tokenized, dtype: object
任何意见将是有益的
您可以使用Counter
:
from collections import Counter
# ... and then
def tokenize(txt):
return Counter(re.split('\W+', txt))
查看 Python 测试:
from collections import Counter
import pandas as pd
import re
Complains = pd.DataFrame({'clean text':['comcast, cable, internet, speeds', 'payment, disappear, service, got, disconnected']})
Complains['clean_text_tokenized'] = Complains['clean text'].str.findall(r'\w+')
freq = Counter([item for sublist in Complains['clean_text_tokenized'].to_list() for item in sublist])
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