遍历字典列表并打印消息

Question

我有一个类似于以下内容的字典列表：

points = [
{"callsign": "A001", "daily_points":10, "number":"+447774076621"},
{"callsign": "A002", "daily_points":5, "number":"+447958708481"}
]

我正在尝试遍历列表以打印如下消息：“嗨 A001，您今天收到了 10 分”

我尝试使用以下代码：

for callsign, daily_points in points.items():
print(f"Hi {callsign} you recieved {daily_points} points today.")

但它返回： AttributeError: 'list' object has no attribute 'items'

我究竟做错了什么？

Answer 1

points是一个列表，而不是一个字典。 您必须遍历列表中的每个元素，然后阅读字典。 代码看起来像这样：

for point in points:
    print(f"Hi {point['callsign']} you received {point['daily_points']} points today.")

Answer 2

您可以使用str.format ：

for point in points:
    print("Hi {callsign} you recieved {daily_points} points today.".format(**point))

此外，由于在 python 3.6+ dict 的保留顺序中，您可以保留大部分代码，只需将points.items()替换为map(dict.values, points) points.items() map(dict.values, points) ：

for callsign, daily_points, *_ in map(dict.values, points):
    print(f"Hi {callsign} you recieved {daily_points} points today.")

Answer 3

变量“points”是字典列表，而不是字典本身。 要遍历列表中的每个字典，您可以：

points = [
{"callsign": "A001", "daily_points":10, "number":"+447774076621"},
{"callsign": "A002", "daily_points":5, "number":"+447958708481"}
]

for point in points:
    print(f"Hi {point['callsign']} you recieved {point['daily_points']} points today.")

这将遍历列表，并打印出每个字典中的信息。

Answer 4

你可以试试这个：

for point in points:
    callsign, daily_points, number = point['callsign'], point['daily_points'], point['number']
    print(f"Hi {callsign} you recieved {daily_points} points today.")

Answer 5

您可以以points遍历每条记录并执行此操作。

for i in range(len(points)):
    print(f"Hi {points[i]['callsign']} you recieved {points[i]['daily_points']} points today.")

输出

Hi A001 you recieved 10 points today.
Hi A002 you recieved 5 points today.

Answer 6

问题是您正在迭代points ，这是一个列表并且没有items属性。

一种方法是使用.format并直接传递字典：

points = [
    {"callsign": "A001", "daily_points": 10, "number": "+447774076621"},
    {"callsign": "A002", "daily_points": 5, "number": "+447958708481"}
]

for d in points:
    print("Hi {callsign} you received {daily_points} points today.".format(**d))

输出

Hi A001 you received 10 points today.
Hi A002 you received 5 points today.

Answer 7

最简单的解决方案如下所示：

for person in points:
    print(f"Hi {person['callsign']} you recieved {person['daily_points']} points today.")

您的解决方案是错误的，因为列表没有方法 items()，并且它无法像这样解压缩字典键。

Answer 8

您需要使用密钥访问该值

for user in points:
    print(f"Hi {user['callsign']} you recieved {user['daily_points']} points today.")

Answer 9

问题是 items() 方法仅适用于列表，不适用于字典。 但是，您可以尝试以下操作：

for dictionary in points:
    print(f"Hi {dictionary['callsign']} you recieved {dictionary['daily_points']} points today.")

或者您可以使用 get() 方法，如下所示：

for dictionary in points:
    print(f"Hi {dictionary.get('callsign')} you recieved {dictionary.get('daily_points')} points today.")

Answer 10

你混合 dict 和 list ..

见下文

points = [{
    "callsign": "A001",
    "daily_points": 10,
    "number": "+447774076621"
}, {
    "callsign": "A002",
    "daily_points": 5,
    "number": "+447958708481"
}]

for point in points:
    print(
        f'Hi {point.get("callsign")} you received {point.get("daily_points")} points today.'
    )

输出

Hi A001 you received 10 points today.
Hi A002 you received 5 points today.