繁体   English   中英

Python从地址生成纬度/经度点

[英]Python generate lat/long points from address

如何在 python 中获取地址并从它们生成经纬度坐标? 我有几个地址想要获得经纬度,但似乎不起作用。

我使用了 geopandas,但它什么也没给我。 我也对user_agent使用什么有点困惑。 这是我的代码,

import pandas as pd
from geopy.geocoders import Nominatim

df2['location_lat'] = ""
df2['location_long'] = ""

geolocator = Nominatim(user_agent="myApp")

for i in df2.index:
    try:
        #tries fetch address from geopy
        location = geolocator.geocode(df2['Location'][i])
        
        #append lat/long to column using dataframe location
        df2.loc[i,'location_lat'] = location.latitude
        df2.loc[i,'location_long'] = location.longitude
  
    except:
        #catches exception for the case where no value is returned
        #appends null value to column
        df2.loc[i,'location_lat'] = ""
        df2.loc[i,'location_long'] = ""
   

任何帮助表示赞赏。 谢谢。

我没有熊猫,但我认为你可以使用它

代码:

from geopy.geocoders import Nominatim

geolocator = Nominatim(user_agent='your_app_name')

addresses = [
            '20, Willmannstraße, Fechenheim, Ost, Frankfurt am Main, Hessen, 60386, Deutschland',
            '20, Willmannstraße, Fechenheim, Ost, Frankfurt am Main, Hessen, 60386, Deutschland',
            'Pöhlen, Schönberg, Sandesneben-Nusse, Herzogtum Lauenburg, Schleswig-Holstein, 22929, Deutschland',
            'Pöhlen, Schönberg, Sandesneben-Nusse, Herzogtum Lauenburg, Schleswig-Holstein, 22929, Deutschland',
            'Pöhlen, Schönberg, Sandesneben-Nusse, Herzogtum Lauenburg, Schleswig-Holstein, 22929, Deutschland'
]

coordinates = []

for address in addresses:
    location = geolocator.geocode(address)

    lat, lon = location.latitude, location.longitude

    coordinates.append((lat, lon))

print(coordinates)

# output:
[(50.1262402, 8.767057053362574),
 (50.1262402, 8.767057053362574),
 (53.6805214, 10.4282207),
 (53.6805214, 10.4282207),
 (53.6805214, 10.4282207)]

希望能帮到你=D

您可以直接在 DataFrame 列上使用apply

import pandas as pd
from geopy.geocoders import Nominatim

geolocator = Nominatim(user_agent="myApp")

df2 = pd.DataFrame({'Location':
            ['2094 Valentine Avenue,Bronx,NY,10457',
             '1123 East Tremont Avenue,Bronx,NY,10460',
             '412 Macon Street,Brooklyn,NY,11233']})

df2[['location_lat', 'location_long']] = df2['Location'].apply(
    geolocator.geocode).apply(lambda x: pd.Series(
        [x.latitude, x.longitude], index=['location_lat', 'location_long']))

它应该给出:

                                  Location  location_lat  location_long
0     2094 Valentine Avenue,Bronx,NY,10457     40.852905     -73.899665
1  1123 East Tremont Avenue,Bronx,NY,10460     40.840130     -73.876245
2       412 Macon Street,Brooklyn,NY,11233     40.682651     -73.934353

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM