替换部分列表元素

Question

我有一个列表变量，其中包含如下元素： ['Cordial/contactactivity/export/bounce/0-ContactActivity-bounce-20211109-131121.csv', 'Cordial/contactactivity/export/bounce/0-ContactActivity-bounce-20211109-131150.csv', 'Cordial/contactactivity/export/bounce/0-ContactActivity-bounce-20211109-131160.csv', 'Cordial/contactactivity/export/bounce/0-ContactActivity-bounce-20211109-131169.csv', 'Cordial/contactactivity/export/bounce/0-ContactActivity-bounce-20211109-131189.csv'] contactactivity ['Cordial/contactactivity/export/bounce/0-ContactActivity-bounce-20211109-131121.csv', 'Cordial/contactactivity/export/bounce/0-ContactActivity-bounce-20211109-131150.csv', 'Cordial/contactactivity/export/bounce/0-ContactActivity-bounce-20211109-131160.csv', 'Cordial/contactactivity/export/bounce/0-ContactActivity-bounce-20211109-131169.csv', 'Cordial/contactactivity/export/bounce/0-ContactActivity-bounce-20211109-131189.csv']

这是包含文件路径的文件名。 想建立一个只有文件名的列表，我该怎么做？ 输出应该是：

['bounce-20211109-131121.csv', 'bounce-20211109-131150.csv', 'bounce-20211109-131160.csv', 'bounce-20211109-131169.csv', 'bounce-20211109-131189.csv']即去掉字符串 'Cordial/contactactivity/export/bounce/0-ContactActivity-'

Answer 1

您可以使用os.path.split （此处的文档）并获取最后一段。 然后你只需要修剪你不想要的部分。

import os
data = [
    'Cordial/contactactivity/export/bounce/0-ContactActivity-bounce-20211109-131121.csv', 
    'Cordial/contactactivity/export/bounce/0-ContactActivity-bounce-20211109-131150.csv',
    'Cordial/contactactivity/export/bounce/0-ContactActivity-bounce-20211109-131160.csv',
    'Cordial/contactactivity/export/bounce/0-ContactActivity-bounce-20211109-131169.csv',
    'Cordial/contactactivity/export/bounce/0-ContactActivity-bounce-20211109-131189.csv'
]
data = [os.path.split(i)[-1].replace('0-ContactActivity-', '') for i in data]

导致：

>>> data
['bounce-20211109-131121.csv', 'bounce-20211109-131150.csv', 'bounce-20211109-131160.csv', 'bounce-20211109-131169.csv', 'bounce-20211109-131189.csv']