I have a list variable which has elemnts like below: ['Cordial/contactactivity/export/bounce/0-ContactActivity-bounce-20211109-131121.csv', 'Cordial/contactactivity/export/bounce/0-ContactActivity-bounce-20211109-131150.csv', 'Cordial/contactactivity/export/bounce/0-ContactActivity-bounce-20211109-131160.csv', 'Cordial/contactactivity/export/bounce/0-ContactActivity-bounce-20211109-131169.csv', 'Cordial/contactactivity/export/bounce/0-ContactActivity-bounce-20211109-131189.csv']
This is file name with file path in it. Want to build a list with only file name, how can i do that? Output should be:
['bounce-20211109-131121.csv', 'bounce-20211109-131150.csv', 'bounce-20211109-131160.csv', 'bounce-20211109-131169.csv', 'bounce-20211109-131189.csv']
ie strip out string 'Cordial/contactactivity/export/bounce/0-ContactActivity-'
You can use os.path.split
( docs here ) and get the last segment. Then you just need to trim the part you don't want.
import os
data = [
'Cordial/contactactivity/export/bounce/0-ContactActivity-bounce-20211109-131121.csv',
'Cordial/contactactivity/export/bounce/0-ContactActivity-bounce-20211109-131150.csv',
'Cordial/contactactivity/export/bounce/0-ContactActivity-bounce-20211109-131160.csv',
'Cordial/contactactivity/export/bounce/0-ContactActivity-bounce-20211109-131169.csv',
'Cordial/contactactivity/export/bounce/0-ContactActivity-bounce-20211109-131189.csv'
]
data = [os.path.split(i)[-1].replace('0-ContactActivity-', '') for i in data]
resulting in:
>>> data
['bounce-20211109-131121.csv', 'bounce-20211109-131150.csv', 'bounce-20211109-131160.csv', 'bounce-20211109-131169.csv', 'bounce-20211109-131189.csv']
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