![](/img/trans.png)
[英]I want to add two df columns df['Date'] and df['hour'] to create the column timestamp
[英]pass two df columns through **kwargs and *args to create a new date column using relativedelta
使用下面的 df,我正在尝试使用 dateutil.relativedelta.relativedelta 确定新日期,但想通过 df['freq'] 和 df['time_int'] 作为 **kwargs 和 *args 进行迭代
In [1]: df
Out[1]:
date time_int freq
0 2021-11-16 -5 days
1 2021-11-16 -1 weeks
2 2021-11-16 -2 weeks
3 2021-11-16 -3 weeks
4 2021-11-16 -3 weeks
5 2021-11-16 -1 months
6 2021-11-16 -1 months
下面,我尝试创建一个 dict 来传递 **kwargs,但 dict 只包含每个键的最后一个值。 我需要它遍历所有键、值组合。
time_dict = dict(zip(df.freq,df.time_int))
df['new_date'] = df['date'].dt.date + relativedelta(**time_dict)
所需的 output:
test
Out[170]:
date time_int freq new_date
0 2021-11-16 -5 days 2021-11-11
1 2021-11-16 -1 weeks 2021-11-09
2 2021-11-16 -2 weeks 2021-11-02
3 2021-11-16 -3 weeks 2021-10-26
4 2021-11-16 -3 weeks 2021-10-26
5 2021-11-16 -1 months 2021-10-16
6 2021-11-16 -1 months 2021-10-16
pandas
已经包含relativedelta
类对象, pandas.DateOffset
您可以使用Series.apply
def compute_new_date(row):
return row['date'] + pd.DateOffset(**{row['freq']: row['time_int']})
# apply compute_new_date row-wise
df['new_date'] = df.apply(compute_new_date, axis=1)
Output:
>>> df
date time_int freq new_date
0 2021-11-16 -5 days 2021-11-11
1 2021-11-16 -1 weeks 2021-11-09
2 2021-11-16 -2 weeks 2021-11-02
3 2021-11-16 -3 weeks 2021-10-26
4 2021-11-16 -3 weeks 2021-10-26
5 2021-11-16 -1 months 2021-10-16
6 2021-11-16 -1 months 2021-10-16
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.