[英]How to add outliers as separate colored markers to a line plot
val time
5.6 2021-11-18 03:00:00
2.034 2021-11-18 05:00:00
1.171 2021-11-18 07:00:00
3.023 2021-11-18 09:00:00
4.202 2021-11-18 16:00:00
1.202 2021-11-18 17:00:00
5.202 2021-11-18 18:00:00
7.202 2021-11-18 19:00:00
2.202 2021-11-18 20:00:00
12.202 2021-11-18 21:00:00
1.202 2021-11-18 21:00:00
上面是我的 dataframe,我想要 plot 它(x=time,y=value),并将值 plot 设为红色,其中(val>5)。
plt.plot(ab['time'], ab['value'], '-gD', markevery=marks, label='line with select markers')
其中标记[7.202,12.202]
是我手动创建的列表。 但这不起作用。 error -: markevery is iterable but not a valid numpy fancy index
如果条件为真 python 3我在这里找到了一个,但如果点很多,这很耗时
pandas.DataFrame.plot
%M-%d %H
。 当有更多数据时格式会改变,还有其他答案讨论如何格式化 pandas 日期时间轴。import pandas as pd
import matplotlib.pyplot as plt
# sample data
data = {'val': [5.6, 2.034, 1.171, 3.023, 4.202, 1.202, 5.202, 7.202, 2.202, 12.202, 1.202], 'time': ['2021-11-18 03:00:00', '2021-11-18 05:00:00', '2021-11-18 07:00:00', '2021-11-18 09:00:00', '2021-11-18 16:00:00', '2021-11-18 17:00:00', '2021-11-18 18:00:00', '2021-11-18 19:00:00', '2021-11-18 20:00:00', '2021-11-18 21:00:00', '2021-11-18 21:00:00']}
df = pd.DataFrame(data)
# convert the time column to a datetime dtype
df.time = pd.to_datetime(df.time)
# get the values greater than 5
masked = df[df.val.gt(5)]
# plot the line plot
ax = df.plot(x='time', marker='o', figsize=(15, 5), zorder=0)
# plot those greater than 5
masked.plot(kind='scatter', x='time', y='val', color='red', ax=ax, s=30, label='outliers')
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.