[英]How to calculate each object in the array in separate array based on truthy condition?
我有这个数组
bidsList = [
{
supplierName:'A',
awardedCapacity:5,
switcherStatus: true
},
{
supplierName:'B',
awardedCapacity:10,
switcherStatus: true,
},
{
supplierName:'A',
awardedCapacity:5,
switcherStatus: false,
},
{
supplierName:'A',
awardedCapacity:3,
switcherStatus: true,
},
{
supplierName:'B',
awardedCapacity:5,
switcherStatus: true,
},
{
supplierName:'C',
awardedCapacity:2,
switcherStatus: false,
},
我需要有单独的数组,当我通过这个数组进行迭代时,我将计算供应商名称相同的所有奖励容量的总数
例如我应该有一个数组,我将有这个 output
let newArr = [
{
supplierName: 'A',
totalAwarded: 13,
},
{
supplierName:'B',
totalAwarded: 15,
},
{
supplierName:'C',
totalAwarded: 2,
}
]
解决方案是:
let newArr = [];
bidsList.reduce(function(acc, val) {
if (!acc[val.supplierName]) {
acc[val.supplierName] = { supplierName: val.supplierName, awardedCapacity: 0 };
newArr.push(acc[val.supplierName])
}
acc[val.supplierName].awardedCapacity += val.awardedCapacity;
return acc;
}, {});
console.log(newArr);
但现在我还需要检查 switcherStatus 是否仅设置为 true - 如果它设置为 false,我不应该计算它的奖励容量,如果它是唯一的一个 object,我不应该推入数组
所以 output 应该是
let newArr = [
{
supplierName: 'A',
totalAwarded: 8,
},
{
supplierName:'B',
totalAwarded: 15,
},
]
C
在这里被排除,因为它是 switcherStatus 假,而 A 是 8 - 因为在 object 上是 switcherStatus 为假
为此,我找不到在这里修改此减少代码的方法。
只需在您的reduce
function 中添加一个条件
var bidsList = [{ supplierName: 'A', awardedCapacity: 5, switcherStatus: true }, { supplierName: 'B', awardedCapacity: 10, switcherStatus: true, }, { supplierName: 'A', awardedCapacity: 5, switcherStatus: false, }, { supplierName: 'A', awardedCapacity: 3, switcherStatus: true, }, { supplierName: 'B', awardedCapacity: 5, switcherStatus: true, }, { supplierName: 'C', awardedCapacity: 2, switcherStatus: false, } ]; var result = bidsList.reduce((a, c) => { if (c.switcherStatus) { let supplier = a.find(e => e.supplierName == c.supplierName); if (supplier) supplier.totalAwarded += c.awardedCapacity; else a.push({ supplierName: c.supplierName, totalAwarded: c.awardedCapacity }); } return a; }, []); console.log(result);
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