如何根據真實條件在單獨的數組中計算數組中的每個 object？

Question

我有這個數組

bidsList = [
    {
      supplierName:'A',
      awardedCapacity:5,
      switcherStatus: true
    },
    {
      supplierName:'B',
      awardedCapacity:10,
      switcherStatus: true,
    },
    {
      supplierName:'A',
      awardedCapacity:5,
      switcherStatus: false,
    },
    {
      supplierName:'A',
      awardedCapacity:3,
      switcherStatus: true,
    },
    {
      supplierName:'B',
      awardedCapacity:5,
      switcherStatus: true,
    },
    {
      supplierName:'C',
      awardedCapacity:2,
      switcherStatus: false,
    },

我需要有單獨的數組，當我通過這個數組進行迭代時，我將計算供應商名稱相同的所有獎勵容量的總數

例如我應該有一個數組，我將有這個 output

 let newArr = [
    {
      supplierName: 'A',
      totalAwarded: 13,
    },
    {
      supplierName:'B',
      totalAwarded: 15,
    },
    {
      supplierName:'C',
      totalAwarded: 2,
    }
  ]

解決方案是：

let newArr = [];
bidsList.reduce(function(acc, val) {
  if (!acc[val.supplierName]) {
    acc[val.supplierName] = { supplierName: val.supplierName, awardedCapacity: 0 };
    newArr.push(acc[val.supplierName])
  }
  acc[val.supplierName].awardedCapacity += val.awardedCapacity;
  return acc;
}, {});

console.log(newArr);

但現在我還需要檢查 switcherStatus 是否僅設置為 true - 如果它設置為 false，我不應該計算它的獎勵容量，如果它是唯一的一個 object，我不應該推入數組

所以 output 應該是

 let newArr = [
    {
      supplierName: 'A',
      totalAwarded: 8,
    },
    {
      supplierName:'B',
      totalAwarded: 15,
    },
  ]

C在這里被排除，因為它是 switcherStatus 假，而 A 是 8 - 因為在 object 上是 switcherStatus 為假

為此，我找不到在這里修改此減少代碼的方法。

Answer 1

只需在您的reduce function 中添加一個條件

 var bidsList = [{ supplierName: 'A', awardedCapacity: 5, switcherStatus: true }, { supplierName: 'B', awardedCapacity: 10, switcherStatus: true, }, { supplierName: 'A', awardedCapacity: 5, switcherStatus: false, }, { supplierName: 'A', awardedCapacity: 3, switcherStatus: true, }, { supplierName: 'B', awardedCapacity: 5, switcherStatus: true, }, { supplierName: 'C', awardedCapacity: 2, switcherStatus: false, } ]; var result = bidsList.reduce((a, c) => { if (c.switcherStatus) { let supplier = a.find(e => e.supplierName == c.supplierName); if (supplier) supplier.totalAwarded += c.awardedCapacity; else a.push({ supplierName: c.supplierName, totalAwarded: c.awardedCapacity }); } return a; }, []); console.log(result);