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[英]Python sort a dict by values, producing a list, how to sort this from largest to smallest?
[英]How to sort default dict with list values in python
我有一个默认字典,列表为
defaultdict(<class 'list'>, {'SOL200122': ['125', '135', '145', '170', '120', '130', '140', '150', '160']}
我希望它像
defaultdict(<class 'list'>, {'SOL200122': ['120', '125', '130', '135', '140', '145', '150', '160', '170']}
试过
sorted(myDict.items(), key=lambda k_v: (k_v[1][2]), reverse=True)
但不工作
将list.sort
与key=int
一起使用(感谢@Metapod、@deceze 等人):
for v in d.values():
v.sort(key=int)
如果你想要一个单行(在这种情况下没有意义,因为 for 循环非常好),我猜像这样的怪物可能是一个:
dict(zip(d.keys(), map(lambda x: sorted(x, key=int), d.values())))
Output:
{'SOL200122': ['120', '125', '130', '135', '140', '145', '150', '160', '170']}
尝试这个:
for v in d.values():
v.sort(key=int)
output:
{'SOL200122': ['120', '125', '130', '135', '140', '145', '150', '160', '170']}
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