如何调用 function 打印在另一个 function 中定义的字符串变量？

Question

所以这是我到目前为止的代码：

age = input("Enter Age: ")


def agePrint():
    print("You have entered " + age + ", which places you in " + ageGroup)

def ageFinder():
    if 00 <= int(age) <= 14:
        ageGroup = "Children"
        agePrint()
    elif 15 <= int(age) <= 24:
        ageGroup = "Youth"
        agePrint()

ageFinder()

所以我想要的不是为每个年龄组手动编写 agePrint function，我只是调用 function，但问题是每个年龄组的年龄组都会发生变化。 所以我必须把它作为变量放在 function 中，但是当我调用agePrint 时，它说没有定义ageGroup。 那么如何定义变量以打印合适的年龄组呢？

Answer 1

您可以将age和ageGroup作为参数：

def agePrint(age, ageGroup):
    print("You have entered " + age + ", which places you in " + ageGroup)

def ageFinder():
    age = input("Enter Age: ")
    if 00 <= int(age) <= 14:
        ageGroup = "Children"
        agePrint(age, ageGroup)
    elif 15 <= int(age) <= 24:
        ageGroup = "Youth"
        agePrint(age, ageGroup)

ageFinder()

Answer 2

将年龄组作为参数传递给 function：

def agePrint(ageGroup):
    print("You have entered " + age + ", which places you in " + ageGroup)

    if 00 <= int(age) <= 14:
        agePrint("Children")
    elif 15 <= int(age) <= 24:
        agePrint("Youth")

Answer 3

您需要将 ageGroup 参数传递给agePrint() function。

def agePrint(ageGroup):
    print("You have entered " + age + ", which places you in " + ageGroup)

def ageFinder():
    if 00 <= int(age) <= 14:
        ageGroup = "Children"
    elif 15 <= int(age) <= 24:
        ageGroup = "Youth"
    agePrint(ageGroup)//Call the agePrint() function out of if block.
    
age = input("Enter Age: ")
ageFinder()

此外，对于 if-elif 块，无需单独调用 agePrint() function。 您可以为 ageGroup 分配一个值，然后调用 function 。

Answer 4

只需将变量作为参数传递给函数：

age = input("Enter Age: ")


def agePrint(age,ageGroup):
    print("You have entered " + age + ", which places you in " + ageGroup)

def ageFinder(age):
    if 00 <= int(age) <= 14:
        ageGroup = "Children"
        agePrint(age,ageGroup)
    elif 15 <= int(age) <= 24:
        ageGroup = "Youth"
        agePrint(age,ageGroup)

ageFinder(age)