如何調用 function 打印在另一個 function 中定義的字符串變量？

Question

所以這是我到目前為止的代碼：

age = input("Enter Age: ")


def agePrint():
    print("You have entered " + age + ", which places you in " + ageGroup)

def ageFinder():
    if 00 <= int(age) <= 14:
        ageGroup = "Children"
        agePrint()
    elif 15 <= int(age) <= 24:
        ageGroup = "Youth"
        agePrint()

ageFinder()

所以我想要的不是為每個年齡組手動編寫 agePrint function，我只是調用 function，但問題是每個年齡組的年齡組都會發生變化。 所以我必須把它作為變量放在 function 中，但是當我調用agePrint 時，它說沒有定義ageGroup。 那么如何定義變量以打印合適的年齡組呢？

Answer 1

您可以將age和ageGroup作為參數：

def agePrint(age, ageGroup):
    print("You have entered " + age + ", which places you in " + ageGroup)

def ageFinder():
    age = input("Enter Age: ")
    if 00 <= int(age) <= 14:
        ageGroup = "Children"
        agePrint(age, ageGroup)
    elif 15 <= int(age) <= 24:
        ageGroup = "Youth"
        agePrint(age, ageGroup)

ageFinder()

Answer 2

將年齡組作為參數傳遞給 function：

def agePrint(ageGroup):
    print("You have entered " + age + ", which places you in " + ageGroup)

    if 00 <= int(age) <= 14:
        agePrint("Children")
    elif 15 <= int(age) <= 24:
        agePrint("Youth")

Answer 3

您需要將 ageGroup 參數傳遞給agePrint() function。

def agePrint(ageGroup):
    print("You have entered " + age + ", which places you in " + ageGroup)

def ageFinder():
    if 00 <= int(age) <= 14:
        ageGroup = "Children"
    elif 15 <= int(age) <= 24:
        ageGroup = "Youth"
    agePrint(ageGroup)//Call the agePrint() function out of if block.
    
age = input("Enter Age: ")
ageFinder()

此外，對於 if-elif 塊，無需單獨調用 agePrint() function。 您可以為 ageGroup 分配一個值，然后調用 function 。

Answer 4

只需將變量作為參數傳遞給函數：

age = input("Enter Age: ")


def agePrint(age,ageGroup):
    print("You have entered " + age + ", which places you in " + ageGroup)

def ageFinder(age):
    if 00 <= int(age) <= 14:
        ageGroup = "Children"
        agePrint(age,ageGroup)
    elif 15 <= int(age) <= 24:
        ageGroup = "Youth"
        agePrint(age,ageGroup)

ageFinder(age)