从字典中获取第二个最大值的键，Python

Question

我正在这样做，但如果有任何简单/有效的方法

def get_second_max(dic):
    count = 0
    ind =0
    vals = list(dic.values())
    for val in vals:
        count = 0
        for value in vals:
            if value > val:
                count += 1
            if count > 2:
                break
        if count == 1:
            ind = vals.index(val)
    return list(dic.keys())[ind]

Answer 1

按值对 dict 键进行排序并获取倒数第二项：

sorted(dic, key=dic.get)[-2]