I am doing it this way but if there is any easy/efficient way of doing it
def get_second_max(dic):
count = 0
ind =0
vals = list(dic.values())
for val in vals:
count = 0
for value in vals:
if value > val:
count += 1
if count > 2:
break
if count == 1:
ind = vals.index(val)
return list(dic.keys())[ind]
Sort the dict keys by their value and get the second to last item:
sorted(dic, key=dic.get)[-2]
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