在 R 中按最近日期合并两个数据框
[英]Merge two dataframes by nearest date in R
问题描述
我有两个数据框，我想在最近的日期之前合并它们。 df2 通常有相同的日期适合 df1。 还有 df2 的值根本不适合 df1。 合并后我想知道合并日期之间的时差。 例如，运送 Sally 适合两个 Peaks，运送 Carl 不适合任何人。 我尝试了不同的解决方案，例如 data.table roll='nearest' function
df1 <- data.frame(date = (c("23.11.2021 20:56:06", "23.11.2021 20:56:07","23.11.2021 20:56:08",
"23.11.2021 20:56:09","23.11.2021 20:56:10",
"23.11.2021 20:56:11", "23.11.2021 22:13:56",
"23.11.2021 22:13:57", "23.11.2021 22:13:58",
"23.11.2021 22:13:59", "24.11.2021 03:23:21",
"24.11.2021 03:23:22", "24.11.2021 03:23:23",
"24.11.2021 03:23:24", "24.11.2021 03:23:25",
"24.11.2021 03:24:34", "24.11.2021 03:24:35",
"24.11.2021 03:24:36", "24.11.2021 03:24:37")),
value = (c(500, 900, 1000, 200, 300, 10, 1000, 450, 950, 600,
100, 750, 150, 200, 300, 400, 900, 1020, 800)))
df2 <- data.frame(date = (c("23.11.2021 20:55:47", "23.11.2021 21:17:48",
"23.11.2021 21:44:19", "23.11.2021 21:55:57",
"23.11.2021 22:16:01","23.11.2021 22:26:35",
"23.11.2021 22:28:43", "23.11.2021 23:14:52",
"23.11.2021 23:32:30","23.11.2021 23:33:43",
"24.11.2021 03:11:30", "24.11.2021 03:23:37",
"24.11.2021 04:42:41", "24.11.2021 04:53:09",
"24.11.2021 04:58:19")),
value = (c("Ship Emma", "Ship Carl", "Ship Rudi", "Ship Tim", "Ship Amy",
"Ship Fred", "Ship Noemi"
, "Ship Fanny", "Ship Ole", "Ship Ally",
"Ship Hugo", "Ship Sally", "Ship Peter", "Ship Harry", "Ship Piet")))
result <- data.frame(date = (c("23.11.2021 20:56:06", "23.11.2021 20:56:07",
"23.11.2021 20:56:08", "23.11.2021 20:56:09",
"23.11.2021 20:56:10","23.11.2021 20:56:11",
"23.11.2021 22:13:56", "23.11.2021 22:13:57",
"23.11.2021 22:13:58", "23.11.2021 22:13:59",
"24.11.2021 03:23:21", "24.11.2021 03:23:22",
"24.11.2021 03:23:23", "24.11.2021 03:23:24",
"24.11.2021 03:23:25", "24.11.2021 03:24:34",
"24.11.2021 03:24:35", "24.11.2021 03:24:36",
"24.11.2021 03:24:37")),
value = (c(500, 900, 1000, 200, 300, 10, 1000, 450, 950, 600,
100, 750, 150, 200, 300, 400, 900, 1020, 800)),
id = (c("Ship Emma", "Ship Emma", "Ship Emma", "Ship Emma", "Ship Emma",
"Ship Emma", "Ship Amy", "Ship Amy", "Ship Amy", "Ship Amy",
"Ship Sally", "Ship Sally", "Ship Sally", "Ship Sally",
"Ship Sally", "Ship Sally", "Ship Sally", "Ship Sally","Ship Sally")),
difference = (c("00:00:19", "00:00:20", "00:00:21", "00:00:22", "00:00:23",
"00:00:24", "00:00:05", "00:00:04", "00:00:03", "00:00:02",
"00:00:16", "00:00:15", "00:00:14", "00:00:13", "00:00:12",
"00:00:57", "00:00:58", "00:00:59", "00:01:00")))
df1$date<- as.POSIXct(df1$date, tz = "GMT", format = "%d.%m.%Y %H:%M:%S")
df2$date<- as.POSIXct(df2$date, tz = "GMT", format = "%d.%m.%Y %H:%M:%S")
result$date<- as.POSIXct(result$date, tz = "GMT", format = "%d.%m.%Y %H:%M:%S")
1 个解决方案
解决方案1
0 已采纳 2022-02-07 10:56:10
我建议两种方法。 第一个使用距离矩阵并执行 df1 到 df2 的左连接。 即距离矩阵由下式给出：
dateDist <- outer(pull(df1, date), pull(df2, date), "-") %>%
abs()
接下来，对于df1的每一行，距离最近的df2行由下式给出：
closest.df1 <- apply(dateDist, 1, which.min)
最后，手动执行合并：
cbind(rename_with(df1, ~paste0("df1.", "", .x)),
rename_with(df2[closest.df1,], ~paste0("df2.", "", .x)))
##>+ df1.date df1.value df2.date df2.value
##>1 2021-11-23 20:56:06 500 2021-11-23 20:55:47 Ship Emma
##>1.1 2021-11-23 20:56:07 900 2021-11-23 20:55:47 Ship Emma
##>1.2 2021-11-23 20:56:08 1000 2021-11-23 20:55:47 Ship Emma
##>1.3 2021-11-23 20:56:09 200 2021-11-23 20:55:47 Ship Emma
##>1.4 2021-11-23 20:56:10 300 2021-11-23 20:55:47 Ship Emma
##>1.5 2021-11-23 20:56:11 10 2021-11-23 20:55:47 Ship Emma
##>5 2021-11-23 22:13:56 1000 2021-11-23 22:16:01 Ship Amy
##>5.1 2021-11-23 22:13:57 450 2021-11-23 22:16:01 Ship Amy
##>5.2 2021-11-23 22:13:58 950 2021-11-23 22:16:01 Ship Amy
##>5.3 2021-11-23 22:13:59 600 2021-11-23 22:16:01 Ship Amy
##>12 2021-11-24 03:23:21 100 2021-11-24 03:23:37 Ship Sally
##>12.1 2021-11-24 03:23:22 750 2021-11-24 03:23:37 Ship Sally
##>12.2 2021-11-24 03:23:23 150 2021-11-24 03:23:37 Ship Sally
##>12.3 2021-11-24 03:23:24 200 2021-11-24 03:23:37 Ship Sally
##>12.4 2021-11-24 03:23:25 300 2021-11-24 03:23:37 Ship Sally
##>12.5 2021-11-24 03:24:34 400 2021-11-24 03:23:37 Ship Sally
##>12.6 2021-11-24 03:24:35 900 2021-11-24 03:23:37 Ship Sally
##>12.7 2021-11-24 03:24:36 1020 2021-11-24 03:23:37 Ship Sally
##>12.8 2021-11-24 03:24:37 800 2021-11-24 03:23:37 Ship Sally
第二种方法涉及首先计算df1和df2的所有行的笛卡尔积，然后仅选择距离最小的行。 这里的技巧是使用inner_join(..., by =character())来获取两个数据帧的所有组合：
mutate(df1, id = row_number()) %>%
inner_join(mutate(df2, id = row_number()),by = character()) |>
mutate(dist = abs(date.x - date.y)) |>
group_by(id.x) |>
filter(dist == min(dist)) |>
select(-id.x, -id.y, -dist)
##>+ # A tibble: 19 × 7
##># Groups: id.x [19]
##> date.x value.x id.x date.y value.y id.y dist
##> <dttm> <dbl> <int> <dttm> <chr> <int> <drtn>
##> 1 2021-11-23 20:56:06 500 1 2021-11-23 20:55:47 Ship Emma 1 19 s…
##> 2 2021-11-23 20:56:07 900 2 2021-11-23 20:55:47 Ship Emma 1 20 s…
##> 3 2021-11-23 20:56:08 1000 3 2021-11-23 20:55:47 Ship Emma 1 21 s…
##> 4 2021-11-23 20:56:09 200 4 2021-11-23 20:55:47 Ship Emma 1 22 s…
##> 5 2021-11-23 20:56:10 300 5 2021-11-23 20:55:47 Ship Emma 1 23 s…
##> 6 2021-11-23 20:56:11 10 6 2021-11-23 20:55:47 Ship Emma 1 24 s…
##> 7 2021-11-23 22:13:56 1000 7 2021-11-23 22:16:01 Ship Amy 5 125 s…
##> 8 2021-11-23 22:13:57 450 8 2021-11-23 22:16:01 Ship Amy 5 124 s…
##> 9 2021-11-23 22:13:58 950 9 2021-11-23 22:16:01 Ship Amy 5 123 s…
##>10 2021-11-23 22:13:59 600 10 2021-11-23 22:16:01 Ship Amy 5 122 s…
##>11 2021-11-24 03:23:21 100 11 2021-11-24 03:23:37 Ship Sally 12 16 s…
##>12 2021-11-24 03:23:22 750 12 2021-11-24 03:23:37 Ship Sally 12 15 s…
##>13 2021-11-24 03:23:23 150 13 2021-11-24 03:23:37 Ship Sally 12 14 s…
##>14 2021-11-24 03:23:24 200 14 2021-11-24 03:23:37 Ship Sally 12 13 s…
##>15 2021-11-24 03:23:25 300 15 2021-11-24 03:23:37 Ship Sally 12 12 s…
##>16 2021-11-24 03:24:34 400 16 2021-11-24 03:23:37 Ship Sally 12 57 s…
##>17 2021-11-24 03:24:35 900 17 2021-11-24 03:23:37 Ship Sally 12 58 s…
##>18 2021-11-24 03:24:36 1020 18 2021-11-24 03:23:37 Ship Sally 12 59 s…
##>19 2021-11-24 03:24:37 800 19 2021-11-24 03:23:37 Ship Sally 12 60 s…
在聚合时按照最接近的前一个日期合并两个数据帧
声明:本站的技术帖子网页，遵循CC BY-SA 4.0协议，如果您需要转载，请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.