[英]Grouping SQL rows based on overlapping active time intervals, valid from and valid to
我正在使用这个模拟数据在 bigquery 中工作:
create schema if not exists dbo;
create table if not exists dbo.player_history(team_id INT, player_id INT, active_from TIMESTAMP, active_to TIMESTAMP);
truncate table dbo.player_history;
INSERT INTO dbo.player_history VALUES(1,1,'2020-01-01', '2020-01-08');
INSERT INTO dbo.player_history VALUES(1,2,'2020-06-01', '2020-09-08');
INSERT INTO dbo.player_history VALUES(1,3,'2020-06-10', '2020-10-01');
INSERT INTO dbo.player_history VALUES(1,4,'2020-02-01', '2020-02-15');
INSERT INTO dbo.player_history VALUES(1,5,'2021-01-01', '2021-01-08');
INSERT INTO dbo.player_history VALUES(1,6,'2021-01-02', '2021-06-08');
INSERT INTO dbo.player_history VALUES(1,7,'2021-01-03', '2021-06-08');
INSERT INTO dbo.player_history VALUES(1,8,'2021-01-04', '2021-06-08');
INSERT INTO dbo.player_history VALUES(1,9,'2020-01-02', '2021-02-05');
INSERT INTO dbo.player_history VALUES(1,10,'2020-10-01', '2021-04-08');
INSERT INTO dbo.player_history VALUES(1,11,'2020-11-01', '2021-05-08');
select *
from dbo.player_history
order by 3, 4
而我想要得到的是活跃的阵容。 output 看起来像这样:
我几乎已经在 valid_to 和 valid_from 之间使用某种 lead(valid_from) 破解了它,并且如果它是一个新的阵容 0 则做一个将它设为 1 的情况,然后对其进行某种累积和以获得 ID但我无法 100% 解决它……我非常绝望,不知道该去哪里找了。
**更正:阵容 4 和 5 实际上应该只是一个阵容。
正如我们在评论部分讨论的那样,鉴于一个玩家可以属于多个阵容,您可以使用JOIN
尝试以下方法:
WITH LINEUPS AS
(SELECT a.*,b.player_id as b_player_id
FROM `dbo.player_history` a
INNER JOIN `dbo.player_history` b on b.active_from BETWEEN a.active_from AND a.active_to
ORDER BY 3, 4)
SELECT
team_id,
ROW_NUMBER () OVER (PARTITION BY team_id ORDER BY active_from, active_to) AS lineup_id,
active_from,
active_to,
ARRAY_AGG(DISTINCT b_player_id) as player_ids
FROM LINEUPS
GROUP BY team_id, active_from, active_to
ORDER BY active_from, active_to
由于 output 太长,我无法通过 Bigquery 控制台中的屏幕截图向您展示,因此我将结果提取到 Google 表格中。 见下图output截图:
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