[英]'expand' won't do what I want. How do I generate a custom list of inputs to a rule in Snakemake?
[英]I always get the final print, even writing the class that I want. How do I fix this?
所以,我只是为了好玩而尝试创建一个角色扮演游戏。 但是,在创建课程时,我注意到我无法选择我的 class。每次我选择 class 时,我总是得到最终打印。 我该如何解决?
while (True):
print("Select your class\n")
print("\nKnight\nArcher\nTank\nRogue\n\n")
classe = input("")
if((classe.strip()).lower() == "Knight"):
forca = 10
defe = 4
hp = 8
agi = 2
inte = 2
break
elif((classe.lower()) == "Archer"):
forca = 6
defe = 6
hp = 6
inte = 8
agi = 7
break
elif((classe.strip()).lower() == "Tank"):
forca = 5
defe = 8
hp = 10
inte = 3
break
elif((class.strip()).lower() == "Rogue"):
strenght += 6
def = 5
hp = 5
inte = 6
agi = 10
break
else:
print("You need to choose one.")
您正在使用.lower()
然后将其与大写字母 ( Tank
) 的单词进行比较。 所以它永远不会匹配。 尝试这个:
while (True):
print("Select your class\n")
print("\nKnight\nArcher\nTank\nRogue\n\n")
classe = input("")
if((classe.strip()).lower() == "knight"):
forca = 10
defe = 4
hp = 8
agi = 2
inte = 2
break
elif((classe.lower()) == "archer"):
forca = 6
defe = 6
hp = 6
inte = 8
agi = 7
break
elif((classe.strip()).lower() == "tank"):
forca = 5
defe = 8
hp = 10
inte = 3
break
# class is a keyword, use classe
elif((classe.strip()).lower() == "rogue"):
# Does this need to be an equals?
strenght = 6
# Def is a keyword, use defe
defe = 5
hp = 5
inte = 6
agi = 10
break
else:
print("You need to choose one.")
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.